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IW1688 参数 Datasheet PDF下载

IW1688图片预览
型号: IW1688
PDF下载: 下载PDF文件 查看货源
内容描述: 低功耗离线式数字PWM控制器,恒流恒压充电,不需光耦和431 [Low-Power Off-line Digital PWM Controller 恒流恒压充电,不需光耦和431]
分类和应用: 控制器
文件页数/大小: 17 页 / 426 K
品牌: ETC [ ETC ]
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iW1688  
Low-Power Off-line Digital PWM Controller  
Calculate CBULK(MIN) and VBULK(MIN)  
2
2
VBULK(MIN) ×TON  
LM =  
(10.4)  
2PIN ×TP ×1.3  
(
)
In typical applications, the bulk capacitor is chosen so that  
the bulk capacitor voltage drops to 70% of the VINDC peak  
before the next charging cycle. (If a longer holdup time is  
needed then a larger bulk capacitor should be used)  
With a known primary inductance of the transformer the  
primary peak current will be:  
VBULK(MIN) = 0.7×125V = 87.5V  
VBULK(MAX ) = VINDC(MAX ) = 372V  
VBULK(MIN) ×TON  
(10.5)  
IPRPK =  
LM  
(10.1)  
PIN  
2
CBULK =  
From equation (10.4) since all factors are known and  
TON(MAX) = 11.3 μs, the primary inductance will be:  
2
fIN × VINDC(MIN) VBULK(MIN)  
(
)
2
932 × 11.3×106  
PIN  
(
)
2
VBULK(MIN) = VINDC(MIN) −  
(10.2)  
LM =  
LM =  
2×5.7× 25×106 ×1.3  
fIN × CBULK  
(
)
3.87mH  
1.3  
With 4 W output and 70% of efficiency power in (PIN) will  
be:  
LM = 2.96mH  
POUT  
(10.3)  
PIN =  
η
From equation (10.5)  
93×11.3×106  
2.96×103  
4W  
IPRPK =  
PIN =  
= 5.7W  
70%  
IPRPK = 355mA  
Substitute value of Pin,VBULK(MIN) and VBULK(MAX) into equation  
(10.1). Solving for CBULK  
:
Calculating the turns ratio:  
5.7  
In Discontinuous Conduction Mode (DCM)  
TP = TON + TRESET + TDEAD  
CBULK =  
=12µF  
1252 87.52 × 60  
(
)
(10.6)  
CBULK = 6.8µF × 2 =13.6µF  
To ensure the circuit remains in DCM a dead time (TDEAD  
)
is established so that the maximum TON plus TRESET is about  
85% of full period (TP or TDEAD is 15% of TP). If TDEAD is more  
than 15% of TP then lower efficiency can be expected. If  
TDEAD is less than 15% then the iW1688 may go into CC  
mode.  
Since we know CBULK then from equation (10.2):  
5.7  
VBULK(MIN) = 1252 −  
60×13.6×106  
VBULK(MIN) = 93V  
TRESET = 85%TP TON  
(10.7)  
Calculating primary inductance and peak current:  
VIN × TON = NVOUT ×TRESET  
The maximum TON is 10.3 μs at a minimum voltage of 93 V.  
The transformer should be designed to meet these operating  
conditions. The primary inductance will be:  
Or:  
VIN × TON  
(10.8)  
N =  
VOUT × TRESET  
2
2
VBULK(MIN) ×TON  
LM =  
2PIN ×TP  
In the worst case of 90VAC input and full load output, then  
from (10.7)  
To minimize the output ripple and noise due to the transition  
between (CV) and (CC) mode or vise versa, we set the CC  
limit up to 130% of the maximum output power, or  
TRESET = 85%× 25µs 11.3µs  
TRESET = 9.95µs  
MK-4AA003-E  
03/16/06  
PAGE 10  
PRELIMINARY  
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