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IW1688 参数 Datasheet PDF下载

IW1688图片预览
型号: IW1688
PDF下载: 下载PDF文件 查看货源
内容描述: 低功耗离线式数字PWM控制器,恒流恒压充电,不需光耦和431 [Low-Power Off-line Digital PWM Controller 恒流恒压充电,不需光耦和431]
分类和应用: 控制器
文件页数/大小: 17 页 / 426 K
品牌: ETC [ ETC ]
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iW1688  
Low-Power Off-line Digital PWM Controller  
Allow a maximum forward voltage drop at the Schottky diode Selecting a switching MOSFET:  
of 0.4 V. Substitute TON and TRESET into equation (10.8):  
For flyback converter the MOSFET will be selected so that  
93×11.3  
5.4×9.95  
VDS is higher than the switching voltages plus reflecting  
secondary and spike voltages.  
N =  
=19.6  
N = 20  
VDS > VBULK(MAX ) + NVOUT +VSPIKE  
(10.13)  
Primary and secondary turns:  
Allow VSPIKE = 100V. From equation (10.13):  
By Faraday law, the number of primary turns will be:  
VDS > 372 + 20 + 5.4 +100 = 580V  
VIN = NPR × AE B / t ×108  
(
)
And IDS > IPRPK = 355mA  
Where V = volt; N = turns; AE = cm²; B = gauss; t = second  
Select a MOSFET = 600 V/0.4 A  
1
Secondary current is a triangle of peak amplitude  
ISECPK = IPRPK x N at a maximum duration of TRESET. It’s RMS  
on a period TP is:  
NPR = VIN   
B  
t  
×108  
AE   
(10.9)  
(10.10)  
(10.11)  
N
TRESET  
TP  
NPR  
(10.14)  
ISECRMS = IPRPK ×  
×
NSEC =  
3
N
Substitute IPRPK = 355mA into equation (10.14)  
NPR ×VAUX  
NAUX =  
VOUT  
355× 20  
9.95  
25  
ISECRMS =  
×
= 2578mA  
3
Select a maximum flux density B = 2500 Gauss and AE =  
0.2 cm². From equation (10.9), (10.10) and (10.11):  
The working voltage of the rectifier diode is included output  
voltage plus reverse voltage at the TON period. A 20%  
marginal voltage is suitable for safety:  
93  
NPR =  
2500  
11.3  
0.2×  
×106 ×108  
VBULK(MAX )  
NPR = 210Turns  
VDIODE =120%  
+VOUT  
N
Since N = 20 and NSEC = 210/20 = 10.5 Turns  
372  
20  
VDIODE =1.2  
+ 5 = 27.3V  
Choose NSEC = 10 Turns and NPR = 200T, Set VAUX = 13V  
13  
NAUX =10×  
= 24Turns  
Typically we select the rated current of a Schottky diode  
rectifier that is twice the output current value. With a known  
value for ISECRMS and VDIODE the rectifier diode will be selected  
as :  
5.4  
Primary RMS current: Primary current is a triangle of peak  
amplitude IPRPK at maximum duration TON. It’s RMS on a  
period TP is:  
Diode = 5A/ 40V  
IPRPK  
TON  
TP  
This RMS current occured at 130% of the output load.  
Therefore the wire size will based on ISECRMS/1.3.  
IPRRMS =  
(10.12)  
3
Substitute IPRPK = 355 mA into equation (10.12)  
355  
3
11.3  
25  
IPRRMS =  
×
=137mA  
MK-4AA003-E  
03/16/06  
PAGE 11  
PRELIMINARY  
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