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P82C250 参数 Datasheet PDF下载

P82C250图片预览
型号: P82C250
PDF下载: 下载PDF文件 查看货源
内容描述: PCA82C250 / 251>CAN收发器 [PCA82C250 / 251 CAN Transceiver]
分类和应用: PC
文件页数/大小: 28 页 / 120 K
品牌: NXP [ NXP ]
 浏览型号P82C250的Datasheet PDF文件第20页浏览型号P82C250的Datasheet PDF文件第21页浏览型号P82C250的Datasheet PDF文件第22页浏览型号P82C250的Datasheet PDF文件第23页浏览型号P82C250的Datasheet PDF文件第24页浏览型号P82C250的Datasheet PDF文件第25页浏览型号P82C250的Datasheet PDF文件第26页浏览型号P82C250的Datasheet PDF文件第28页  
Philips Semiconductors  
PCA82C250 / 251 CAN Transceiver  
Application Note  
AN96116  
APPENDIX 2 CALCULATION OF THE VOLTAGE AT THE INPUT OF A NODE  
For the calculation of the worst case (i.e. minimum) differential input voltage at the receiving node the following  
assumptions or simplifications are made (see also Fig. 7 and Fig. 10):  
The termination resistors (R ) are located at the output of the transmitting and at the input of the receiving  
T
node.  
The resistance of the lines between the transmitting and the receiving node is represented by the resistors  
R .  
W
All other nodes are at the same end of the transmission line as the receiving node resulting in the minimum dif-  
ferential input voltage.  
The output voltage of the transmitting node (V  
) is supposed to be generated by a voltage source.  
diff.out  
output of  
input of  
transmitting  
node (1)  
receiving  
node (n)  
node inputs  
(2...n-1)  
bus wiring  
termination  
termination  
I
W
R
W
R
(n-2)  
diff  
R
V
R
T
R
diff.out  
diff  
T
V
diff.in  
I
I
T1  
in  
I
I
T2  
in(n-2)  
R
W
I
W
Fig. 10 Circuit diagram used for the calculation of the differential input voltage at the receiver node.  
Thus the relation between the achievable differential input voltage at the receiving node and the differential out-  
put voltage of the transmitting node is given by:  
V
= V  
+ 2 × R × I  
W
(14)  
diff.out  
diff.in  
W
The current I flowing through the bus lines splits up in I  
(input current of the connected nodes without the  
in(n-2)  
W
transmitting and receiving one), I (current flowing through the termination resistor) and I (input current of the  
T2  
in  
receiving node) as shown in Fig. 10.  
With  
I
= I  
+ I + I  
in  
and  
W
in(n – 2)  
T2  
R
diff  
V
= I  
× ----------- and V  
= I × R  
and V  
= I × R  
diff.in in diff  
diff.in  
in(n – 2)  
diff.in  
T2  
T
n – 2  
the relation between V  
and V  
is calculated from equation (14)  
27  
diff.out  
diff.in  
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