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CS51313GDR16 参数 Datasheet PDF下载

CS51313GDR16图片预览
型号: CS51313GDR16
PDF下载: 下载PDF文件 查看货源
内容描述: CPU同步降压控制器能够实现多线性稳压器 [Synchronous CPU Buck Controller Capable of Implementing Multiple Linear Regulators]
分类和应用: 稳压器控制器
文件页数/大小: 20 页 / 249 K
品牌: CHERRY [ CHERRY SEMICONDUCTOR CORPORATION ]
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Application Information: continued  
Two considerations complicate the task of estimating  
V  
LIN  
=
,
switching times. First, since the magnitude of the input  
capacitance, CISS, varies with VDS, the RC time constant  
determined by the gate-drive impedance and CISS changes  
during the switching cycle. Consequently, computation of  
the rise time of the gate voltage by using a specific gate-  
drive impedance and input capacitance yields only a  
rough estimate. The second consideration is the effect of  
the “Miller” capacitance, CRSS, which is referred to as CDG  
in the following discussion. For example, when a device is  
on, VDS(ON) is fairly small and VGS is about 12V. CDG is  
charged to VDS(ON) VGS, which is a negative potential if  
the drain is considered the positive electrode. When the  
drain is “off”, CDG is charged to quite a different potential.  
In this case the voltage across CDG is a positive value since  
the potential from gate-to-source is near zero volts and VDS  
is essentially the drain supply voltage. During turn-on and  
turn-off, these large swings in gate-to-drain voltage tax the  
current sourcing and sinking capabilities of the gate drive.  
In addition to charging and discharging CGS, the gate drive  
must also supply the displacement current required by  
CDG(IGATE = Cdg dVdg/dt). Unless the gate-drive  
(dI/dt)MAX  
where  
LIN = input inductor value;  
V = voltage seen by the input inductor during a full  
load swing;  
(dI/dt)MAX = maximum allowable input current slew  
rate (0.1A/µs for a Pentium® II power supply).  
The designer must select the LC filter pole frequency so  
that at least 40dB attenuation is obtained at the regulator  
switching frequency. The LC filter is a double-pole net-  
work with a slope of 2, a roll-off rate of –40dB/dec, and a  
corner frequency:  
1
fC =  
,
2π LC  
where  
L = input inductor;  
C = input capacitor(s).  
impedance is very low, the VGS waveform commonly  
plateaus during rapid changes in the drain-to-source volt-  
age.  
Step 7: Selection of the Switching FET  
FET Basics  
The most important aspect of FET performance is the Static  
Drain-To-Source On-Resistance (RDS(ON)), which effects  
regulator efficiency and FET thermal management require-  
ments. The On-Resistance determines the amount of cur-  
rent a FET can handle without excessive power dissipation  
that may cause overheating and potentially catastrophic  
failure. As the drain current rises, especially above the con-  
tinuous rating, the On-Resistance also increases. Its posi-  
tive temperature coefficient is between +0.6%/C and  
+0.85%/C. The higher the On-Resistance the larger the  
conduction loss is. Additionally, the FET gate charge  
should be low in order to minimize switching losses and  
reduce power dissipation.  
Both logic level and standard FETs can be used. The refer-  
ence designs derive gate drive from the 12V supply, which  
is generally available in most computer systems and uti-  
lizes logic level FETs.  
Voltage applied to the FET gates depends on the applica-  
tion circuit used. Both upper and lower gate driver outputs  
are specified to drive to within 1.5V of ground when in the  
low state and to within 2V of their respective bias supplies  
when in the high state. In practice, the FET gates will be  
driven rail-to-rail due to overshoot caused by the capaci-  
tive load they present to the controller IC.  
The use of the MOSFET as a power switch is propelled by  
two reasons: 1) Its very high input impedance; and 2) Its very  
fast switching times. The electrical characteristics of a MOS-  
FET are considered to be those of a perfect switch. Control  
and drive circuitry power is therefore reduced. Because the  
input impedance is so high, it is voltage driven. The input  
of the MOSFET acts as if it were a small capacitor, which  
the driving circuit must charge at turn on. The lower the  
drive impedance, the higher the rate of rise of VGS, and the  
faster the turn- on time. Power dissipation in the switching  
MOSFET consists of 1) conduction losses, 2) leakage losses,  
3) turn-on switching losses, 4) turn-off switching losses,  
and 5) gate-transitions losses. The latter three losses are  
proportional to frequency. For the conducting power dissi-  
pation rms values of current and resistance are used for  
true power calculations. The fast switching speed of the  
MOSFET makes it indispensable for high-frequency power  
supply applications. Not only are switching power losses  
minimized, but also the maximum usable switching fre-  
quency is considerably higher. Switching time is indepen-  
dent of temperature. Also, at higher frequencies, the use of  
smaller and lighter components (transformer, filter choke,  
filter capacitor) reduces overall component cost while  
using less space for more efficient packaging at lower  
weight.  
The MOSFET has purely capacitive input impedance. No  
DC current is required. It is important to keep in mind the  
drain current of the FET has a negative temperature coeffi-  
cient. Increase in temperature causes higher on-resistance  
and greater leakage current. For switching circuits, VDS(ON)  
should be low to minimize power dissipation at a given ID,  
and VGS should be high to accomplish this. MOSFET  
switching times are determined by device capacitance,  
stray capacitance, and the impedance of the gate drive cir-  
cuit. Thus the gate driving circuit must have high momen-  
tary peak current sourcing and sinking capability for  
switching the MOSFET. The input capacitance, output  
capacitance and reverse-transfer capacitance also increase  
with increased device current rating.  
Step 7a - Selection of the switching (upper) FET  
The designer must ensure that the total power dissipation  
in the FET switch does not cause the power component’s  
junction temperature to exceed 150°C.  
The maximum RMS current through the switch can be  
determined by the following formula:  
IRMS(H)  
=
(IL(PEAK)2 + (IL(PEAK) × IL(VALLEY)) + IL(VALLEY)2 × D  
,
3
14  
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