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WM8216SEFL/R 参数 Datasheet PDF下载

WM8216SEFL/R图片预览
型号: WM8216SEFL/R
PDF下载: 下载PDF文件 查看货源
内容描述: 60MSPS 10位2通道CCD数字转换器 [60MSPS 10-bit 2-channel CCD Digitiser]
分类和应用: 转换器
文件页数/大小: 27 页 / 460 K
品牌: WOLFSON [ WOLFSON MICROELECTRONICS PLC ]
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WM8216  
Production Data  
The ADC BLOCK then converts the analogue signal, V3, to a 10-bit unsigned digital output, D1.  
The digital output is then inverted, if required, through the OUTPUT INVERT BLOCK to produce D2.  
CALCULATING THE OUTPUT CODE FOR A GIVEN INPUT  
The following equations describe the processing of the video and reset level signals through  
the WM8216.  
INPUT SAMPLING BLOCK: INPUT SAMPLING AND REFERENCING  
If CDS = 1, (i.e. CDS operation) the previously sampled reset level, VRESET, is subtracted from the  
input video.  
V1  
=
VIN - VRESET  
Eqn. 1  
If CDS = 0, (non-CDS operation) the simultaneously sampled voltage on pin VRLC is subtracted  
instead.  
V1  
=
VIN - VVRLC  
Eqn. 2  
If VRLCDACPD = 1, VVRLC is an externally applied voltage on pin VRLC/VBIAS.  
If VRLCDACPD = 0, VVRLC is the output from the internal RLC DAC.  
VVRLC  
=
(VRLCSTEP RLC DAC[3:0]) + VRLCBOT  
Eqn. 3  
VRLCSTEP is the step size of the RLC DAC and VRLCBOT is the minimum output of the RLC DAC.  
OFFSET DAC BLOCK: OFFSET (BLACK-LEVEL) ADJUST  
The resultant signal V1 is added to the Offset DAC output.  
V2  
=
V1 + {255mV (DAC[7:0]-127.5) } / 127.5  
Eqn. 4  
Eqn. 5  
PGA NODE: GAIN ADJUST  
The signal is then multiplied by the PGA gain.  
V3  
=
V2 (0.66 + PGA[8:0]x7.34/511)  
ADC BLOCK: ANALOGUE-DIGITAL CONVERSION  
The analogue signal is then converted to a 10-bit unsigned number, with input range configured by  
PGAFS[1:0].  
D1[9:0] = INT{ (V3 /VFS) 1023} + 511  
D1[9:0] = INT{ (V3 /VFS) 1023}  
PGAFS[1:0] = 00 or 01  
PGAFS[1:0] = 11  
Eqn. 6  
Eqn. 7  
Eqn. 8  
D1[9:0] = INT{ (V3 /VFS) 1023} + 1023  
PGAFS[1:0] = 10  
where the ADC full-scale range, VFS = 2V when LOWREFS=0 and VFS = 1.2V when LOWREFS=1.  
OUTPUT INVERT BLOCK: POLARITY ADJUST  
The polarity of the digital output may be inverted by control bit INVOP.  
D2[9:0] = D1[9:0]  
(INVOP = 0)  
(INVOP = 1)  
Eqn. 9  
D2[9:0] = 1023 – D1[9:0]  
Eqn. 10  
PD Rev 4.0 March 2007  
18  
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