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ST92F150JDV1Q6 参数 Datasheet PDF下载

ST92F150JDV1Q6图片预览
型号: ST92F150JDV1Q6
PDF下载: 下载PDF文件 查看货源
内容描述: 8月16日- BIT单电压闪存单片机系列内存, E3 TMEMULATED EEPROM , CAN 2.0B和J1850 BLPD [8/16-BIT SINGLE VOLTAGE FLASH MCU FAMILY WITH RAM, E3 TMEMULATED EEPROM, CAN 2.0B AND J1850 BLPD]
分类和应用: 闪存微控制器和处理器外围集成电路光电二极管可编程只读存储器电动程控只读存储器电可擦编程只读存储器时钟
文件页数/大小: 426 页 / 3830 K
品牌: STMICROELECTRONICS [ ST ]
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ST92F124/F150/F250 - RESET AND CLOCK CONTROL UNIT (RCCU)  
CLOCK MANAGEMENT (Cont’d)  
7.3.6 Interrupt Generation  
– when the system clock restarts after a hardware  
stop (when the STOP MODE feature is availa-  
ble on the specific device).  
System clock selection modifies the CLKCTL and  
CLK_FLAG registers.  
– when the PLL loses the programmed frequency  
in which it was locked, and when it re-locks  
The clock control unit generates an external inter-  
rupt request (INTD0) in the following conditions:  
This interrupt can be masked by resetting the  
INT_SEL bit in the CLKCTL register. Note that this  
is the only case in the ST9 where an interrupt is  
generated with a high to low transition.  
– when CK_AF and CLOCK2/16 are selected or  
deselected as system clock source,  
Table 27. Summary of Operating Modes using main Crystal Controlled Oscillator  
WFI_CK  
SEL  
MODE  
PLL x BY 14  
PLL x BY 10  
PLL x BY 8  
PLL x BY 6  
SLOW 1  
INTCLK CPUCLK DIV2 PRS0-2 CSU_CKSEL MX0-1 DX2-0 LPOWFI  
XT_DIV16  
XTAL/2  
x (14/D)  
INTCLK/  
N
1
1
1
1
1
N-1  
N-1  
N-1  
N-1  
N-1  
1
1
1
1
X
1 0  
0 0  
1 1  
0 1  
X
D-1  
D-1  
D-1  
D-1  
111  
X
X
X
X
X
X
X
X
X
X
1
1
1
1
1
XTAL/2  
x (10/D)  
INTCLK/  
N
XTAL/2  
x (8/D)  
INTCLK/  
N
XTAL/2  
x (6/D)  
INTCLK/  
N
INTCLK/  
N
XTAL/2  
INTCLK/  
N
SLOW 2  
XTAL/32  
1
N-1  
N-1  
X
X
X
X
X
X
X
X
X
X
0
SLOW3  
WFI  
CK_AF CK_AF/N  
X
X
If LPOWFI=0, no changes occur on INTCLK, but CPUCLK is stopped anyway.  
LOW POW-  
ER WFI 1  
XTAL/32  
STOP  
1
X
X
X
X
1
0
X
LOW POW-  
ER WFI 2  
CK_AF  
XTAL/2  
STOP  
1
1
X
0
X
0
X
X
1
0
1
0
X
1
RESET  
INTCLK  
00  
111  
EXAMPLE  
XTAL=4.4  
MHz  
2.2*10/2  
= 11MHz  
11MHz  
1
0
1
00  
001  
X
1
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