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NCP1252 参数 Datasheet PDF下载

NCP1252图片预览
型号: NCP1252
PDF下载: 下载PDF文件 查看货源
内容描述: 反激应用 [Flyback Applications]
分类和应用:
文件页数/大小: 17 页 / 249 K
品牌: ONSEMI [ ONSEMI ]
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NCP1252  
Vdd  
Clock  
S
FB  
2R  
R
DRV  
path  
Q
Q
Buffered  
Ramp  
R
Rramp  
Rcomp CS  
LEB  
+
Rsense  
Ccs  
Figure 34. Ramp Compensation Setup  
In the NCP1252, the internal ramp swings with a slope of:  
A few line of algebra determined Rcomp:  
Vramp  
Ratio  
Rcomp + R  
(eq. 9)  
ramp 1 * Ratio  
Sint  
+
FSW  
(eq. 6)  
DCmax  
The previous ramp compensation calculation does not  
take into account the natural primary ramp created by the  
transformer magnetizing inductance. In some case  
illustrated here after the power supply does not need  
additional ramp compensation due to the high level of the  
natural primary ramp.  
In a forward application the secondaryside downslope  
viewed on a primary side requires a projection over the sense  
resistor R  
. Thus:  
sense  
(Vout ) Vf)  
Ns  
Np  
Ssense  
+
Rsense  
(eq. 7)  
Lout  
The natural primary ramp is extracted from the following  
formula:  
where:  
V is output voltage level  
out  
Vbulk  
Lmag  
V the freewheel diode forward drop  
f
Snatural  
+
Rsense  
(eq. 10)  
L , the secondary inductor value  
out  
Then the natural ramp compensation will be:  
N /N the transformer turn ratio  
s
p
R  
: the sense resistor on the primary side  
Snatural  
Ssense  
sense  
dnatural_comp  
+
(eq. 11)  
Assuming the selected amount of ramp compensation to  
be applied is δ , then we must calculate the division ratio  
comp  
If the natural ramp compensation (δ  
) is higher  
), the power  
natural_comp  
to scale down S accordingly:  
int  
than the ramp compensation needed (δ  
comp  
R
sensedcomp  
Sint  
supply does not need additional ramp compensation. If not,  
Ratio +  
(eq. 8)  
only the difference (δ  
δ  
) should be used to  
calculate the accurate compensation value.  
comp natural_comp  
Thus the new division ratio is:  
S
sense(dcomp * dnatural_comp  
)
if dnatural_comp t dcomp å Ratio +  
(eq. 12)  
Sint  
Then R  
can be calculated with the same equation used  
V  
= 350 V, minimum input voltage at which the  
power supply works.  
comp  
bulk  
when the natural ramp is neglected (Equation 9).  
Duty cycle max: DC  
= 84%  
max  
Ramp Compensation Design Example:  
2 switchForward Power supply specification:  
V  
R  
= 3.5 V, Internal ramp level.  
ramp  
= 26.5 kW, Internal pullup resistance  
Regulated output: 12 V  
ramp  
Targeted ramp compensation level: 100%  
Transformer specification:  
L = 27 mH  
out  
V = 0.7 V (drop voltage on the regulated output)  
f
L  
= 13 mH  
mag  
Current sense resistor : 0.75 W  
Switching frequency : 125 kHz  
N /N = 0.085  
s
p
http://onsemi.com  
15  
 
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