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MAX1908|MAX8724 参数 Datasheet PDF下载

MAX1908|MAX8724图片预览
型号: MAX1908|MAX8724
PDF下载: 下载PDF文件 查看货源
内容描述: 低成本,多种电池充电器\n [Low-Cost Multichemistry Battery Chargers ]
分类和应用: 电池
文件页数/大小: 27 页 / 604 K
品牌: MAXIM [ MAXIM INTEGRATED PRODUCTS ]
 浏览型号MAX1908|MAX8724的Datasheet PDF文件第16页浏览型号MAX1908|MAX8724的Datasheet PDF文件第17页浏览型号MAX1908|MAX8724的Datasheet PDF文件第18页浏览型号MAX1908|MAX8724的Datasheet PDF文件第19页浏览型号MAX1908|MAX8724的Datasheet PDF文件第21页浏览型号MAX1908|MAX8724的Datasheet PDF文件第22页浏览型号MAX1908|MAX8724的Datasheet PDF文件第23页浏览型号MAX1908|MAX8724的Datasheet PDF文件第24页  
Low-Cost Multichemistry Battery Chargers  
where R varies with load according to R = V / I  
BATT CHG.  
L
L
Output zero due to output capacitor ESR:  
BATT  
1
f
=
GM  
OUT  
Z _ESR  
2πR  
× C  
OUT  
ESR  
The loop transfer function is given by:  
LTF = GM ×R ×GMV ×R ×  
OGMV  
R
R
L
ESR  
CCV  
OUT  
L
GMV  
C
OUT  
1+sC  
× R  
1+sC × R  
(
)(  
)
)
OUT  
ESR CV CV  
1+sC × R  
1+sC  
)(  
× R  
L
(
CV  
OGMV  
OUT  
R
CV  
R
OGMV  
REF  
Assuming the compensation pole is a very low  
frequency, and the output zero is a much higher fre-  
quency, the crossover frequency is given by:  
C
CV  
GMV × R  
× GM  
OUT  
CV  
f
=
CO_CV  
Figure 5. CCV Loop Diagram  
2πC  
OUT  
CCV Loop Definitions  
Compensation of the CCV loop depends on the para-  
meters and components shown in Figure 5. C and  
To calculate R and C values of the circuit of Figure 2:  
Cells = 4  
CV  
CV  
CV  
C
OUT  
= 22µF  
R
are the CCV loop compensation capacitor and  
CV  
V
I
= 16.8V  
= 2.5A  
BATT  
CHG  
series resistor. R  
(ESR) of the charger output capacitor (C  
equivalent charger output load, where R = V  
CHG  
is the equivalent series resistance  
ESR  
). R is the  
L
OUT  
/
BATT  
GMV = 0.125µA/mV  
L
I
. The equivalent output impedance of the GMV  
GM  
= 3.33A/V  
OUT  
amplifier, R  
10M. The voltage amplifier  
OGMV  
R
OGMV  
= 10MΩ  
transconductance, GMV = 0.125µA/mV. The DC-DC  
converter transconductance, GM = 3.33A/V:  
f = 400kHz  
OUT  
Choose crossover frequency to be 1/5th the  
MAX1908’s 400kHz switching frequency:  
1
GM  
=
OUT  
A
× RS2  
CSI  
GMV × R  
× GM  
OUT  
CV  
f
=
= 80kHz  
CO_CV  
2πC  
OUT  
where A  
= 20, and RS2 is the charging current-  
CSI  
sense resistor in the Typical Application Circuits.  
Solving yields R = 26k.  
CV  
The compensation pole is given by:  
Conservatively set R = 1k, which sets the crossover  
CV  
frequency at:  
1
f
=
P _CV  
f
= 3kHz  
2πR  
× C  
CV  
CO_CV  
OGMV  
Choose the output-capacitor ESR such that the output-  
capacitor zero is 10 times the crossover frequency:  
The compensation zero is given by:  
1
1
f
=
R
=
= 0.24Ω  
Z _CV  
ESR  
2πR  
× C  
CV  
2π ×10× f  
×C  
OUT  
CV  
CO_CV  
The output pole is given by:  
1
f
=
= 2.412MHz  
Z_ESR  
2πR  
×C  
1
ESR  
OUT  
f
=
P _OUT  
2πR × C  
L
OUT  
20 ______________________________________________________________________________________  
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