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LM396 参数 Datasheet PDF下载

LM396图片预览
型号: LM396
PDF下载: 下载PDF文件 查看货源
内容描述: 10安培可调稳压( 295.73 K)\n [10 Amp Adjustable Voltage Regulator(295.73 k) ]
分类和应用:
文件页数/大小: 14 页 / 297 K
品牌: ETC [ ETC ]
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Application Hints (Continued)  
e
e
V
V
I
Nominal line voltage AC rms  
Low line voltage AC rms  
NOM  
Input and Output Capacitors  
LOW  
The LM196 will tolerate a wide range of input and output  
capacitance, but long wire runs or small values of output  
capacitance can sometimes cause problems. If an output  
capacitor is used, it should be 1 mF or larger. We suggest 10  
mF solid tantalum if significant improvements in high fre-  
quency output impedance are needed (see output imped-  
ance graph). This capacitor should be as close to the regu-  
lator as possible, with short leads, to reduce the effects of  
lead inductance. No input capacitor is needed if the regula-  
tor is within 6 inches of the power supply filter capacitor,  
using 18 gauge stranded wire. For longer wire runs, the  
LM196 input should be bypassed locally with a 4.7 mF (or  
larger) solid tantalum capacitor, or a 100 mF (or larger) alu-  
minum electrolytic capacitor.  
e
DC output current  
OUT  
e
e
Example: I  
10A, V  
OUT  
5V  
OUT  
e
e
Assume: V  
2.2V, V  
1.2V  
REG  
RECT  
e
e
V
V
5
2 Vp-p, V  
115V,  
RIPPLE  
NOM  
e
105V  
LOW  
a
a
a
1.2 1  
2.2  
115  
e
e
V
rms  
1.1  
2
105  
#
0
(5.3 10 ) (I  
J # J  
8.01 V  
rms  
b
3
c
)
OUT  
e
Capacitor C  
c
2
V
RIPPLE  
b
3
c
(5.3 10 )(10)  
2
e
e
26,500 mF  
Correcting for Output Wire Losses (LM196/LM396)  
The diodes used in a full-wave rectified capacitor input sup-  
ply must have a DC current rating considerably higher than  
the average current flowing through them. In a 10A supply,  
for instance, the average current through each diode is only  
5A, but the diodes should have a rating of 10A15A. There  
are many reasons for this, both thermal and electrical. The  
diodes conduct current in pulses about 3.5 ms wide with a  
peak value of 5–8 times the average value, and an rms  
value 1.52.0 times the average value. This results in long  
term diode heating roughly equivalent to 10A DC current.  
The most demanding condition however, may be the one  
cycle surge through the diode during power turn on. The  
peak value of the surge is about 1020 times the DC output  
current of the supply, or 100A200A for a 10A supply. The  
diodes must have a one cycle non-repetitive surge rating of  
200A or more, and this is usually not found in a diode with  
less than 10A average current rating. Keep in mind that  
even though the LM196 may be used at current levels be-  
low 10A, the diodes may still have to survive shorted output  
conditions where average current could rise to 12A15A.  
Smaller transformers and filter capacitors used in lower cur-  
rent supplies will reduce surge currents, but unless specific  
information is available on worst-case surges, it is best not  
to economize on diodes. Stud-mounted devices in a DO-4  
package are recommended. Cathode-to-case types may be  
bolted directly to the same heat sink as the LM196 because  
the case of the regulator is its power input. Part numbers to  
consider are the 1N1200 series rated at 12A average cur-  
rent in a DO-4 stud package. Additional types include com-  
mon cathode duals in a TO-3 package, both standard and  
Schottky, and various duals in plastic filled assemblies.  
Schottky diodes will improve efficiency, especially in low  
voltage applications. In a 5V supply for instance, Schottky  
diodes will decrease wasted power by up to 6W, or alterna-  
tively provide an additional 5% ‘‘drop out’’ margin for low-  
line conditions. Several manufacturers are producing ‘‘high  
efficiency’’ diodes with a forward voltage drop nearly as  
good as Schottkys at high current levels. These devices do  
not have the low breakdown voltages of Schottkys, so are  
much less prone to reverse breakdown induced failures.  
Three-terminal regulators can only provide partial Kelvin  
load sensing (see Load Regulation). Full remote sensing  
can be added by using an external op amp to cancel the  
effect of voltage drops in the unsensed positive output lead.  
In Figure 7, the LM301A op amp forces the voltage loss  
across the unsensed output lead to appear across R3. The  
current through R3 then flows out the Vb pin of the op amp  
through R4. The voltage drop across R4 will raise the output  
voltage by an amount equal to the line loss, just cancelling  
j
the line loss itself. A small ( 40 mV) initial output voltage  
error is created by the quiescent current of the op amp.  
Cancellation range is limited by the maximum output current  
of the op amp, about 300 mV as shown. This can be raised  
by increasing R3 or R4 at the expense of more initial output  
error.  
Transformers and Diodes  
Proper transformer ratings are very important in a high cur-  
rent supply because of the conflicting requirements of effi-  
ciency and tolerance to low-line conditions. A transformer  
with a high secondary voltage will waste power and cause  
unnecessary heating in the regulator. Too low a secondary  
voltage will cause loss of regulation under low-line condi-  
tions. The following formulas may be used to calculate the  
required secondary voltage and current ratings using a full-  
wave center tap:  
a
a
a
V
RECT  
V
V
V
OUT  
REG  
RIPPLE  
e
V
rms  
2
#
0
J
Minimum input-output voltage of regulator  
V
NOM  
*
(1.1)  
V
# J # J  
LOW  
e
I
(I  
) (1.2)  
(Full-wave center tap)  
rms  
where:  
OUT  
e
e
V
V
V
DC regulated output voltage  
OUT  
REG  
e
Rectifier forward voltage drop at three times DC  
output current  
RECT  
e
V
1/2 peak-to-peak capacitor ripple voltage  
b
RIPPLE  
3
(5.3 10 ) (I  
c
)
OUT  
e
2C  
*The factor of 1.1 is only an approximate factor accounting for load regula-  
tion of the transformer.  
6
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