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LTC3649IFE#PBF 参数 Datasheet PDF下载

LTC3649IFE#PBF图片预览
型号: LTC3649IFE#PBF
PDF下载: 下载PDF文件 查看货源
内容描述: [LTC3649 - 60V, 4A Synchronous Step-Down Regulator with Rail-to-Rail Programmable Output; Package: TSSOP; Pins: 28; Temperature Range: -40°C to 85°C]
分类和应用: 开关光电二极管输出元件
文件页数/大小: 26 页 / 487 K
品牌: Linear [ Linear ]
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LTC3649  
APPLICATIONS INFORMATION  
2
1. I R losses are calculated from the DC resistances of  
diodeconductionlossesduringdead-timeandinductor  
core losses which generally account for less than 28  
total additional loss.  
the internal switches, R , and external inductor, R .  
SW  
L
In continuous mode, the average output current flows  
through inductor L but is “chopped” between the  
internal top and bottom power MOSFETs. Thus, the  
series resistance looking into the SW pin is a function  
Thermal Conditions  
In a majority of applications, the LTC3649 does not dis-  
sipatemuchheatduetoitshighefficiencyandlowthermal  
resistanceofitsexposed-backQFNandFEpackages.How-  
ever, in applications where the LTC3649 is running at high  
of both top and bottom MOSFET R  
cycle (D) as follows:  
and the duty  
DS(ON)  
R
SW  
= (R )(D) + (R )(1 – D)  
DS(ON)TOP DS(ON)BOT  
ambient temperature, high V , high switching frequency,  
IN  
TheR  
forboththetopandbottomMOSFETscanbe  
DS(ON)  
and maximum output current load, the heat dissipated  
may exceed the maximum junction temperature of the  
part. If the junction temperature reaches approximately  
1ꢀ0°C, both power switches will be turned off until the  
temperature drops by 15°C.  
obtained from the Typical Performance Characteristics  
2
curves. Thus to obtain I R losses:  
2
2
I R losses = I  
(R + R )  
SW L  
OUT  
2. The switching current is the sum of the MOSFET driver  
and control currents. The power MOSFET driver cur-  
rent results from switching the gate capacitance of  
the power MOSFETs. Each time a power MOSFET gate  
is switched from low to high to low again, a packet of  
charge dQ moves from IN to ground. The resulting dQ/  
dt is a current out of IN that is typically much larger  
than the DC control bias current. In continuous mode:  
To avoid the LTC3649 from exceeding the maximum junc-  
tion temperature, some thermal analysis must be done.  
The goal of the thermal analysis is to determine whether  
the power dissipated exceeds the maximum junction  
temperature of the part. The temperature rise is given by:  
T
RISE  
= P θ  
D JA  
As an example, consider the case when the LTC3649  
is used in applications where V = 24V, I = 4A,  
I
= f(Q + Q )  
T B  
GATECHG  
IN  
OUT  
where Q and Q are the gate charges of the internal  
top and bottom power MOSFETs and f is the switching  
frequency. The power loss is thus:  
T
B
f = 1MHz, and V  
= 3.3V. The equivalent power MOSFET  
OUT  
resistance R is:  
SW  
VOUT  
V
V
IN  
Switching Loss = I  
• V  
IN  
OUT   
GATECHG  
RSW =RDS(ON)TOP  
+RDS(ON)BOT • 1−  
V
IN  
The gate charge loss is a function of current through  
the INTV pin as well as frequency. Thus, their effects  
3.3V  
24V  
3.3V  
24V  
CC  
= 110m•  
= 5ꢀ.25mΩ  
+50m• 1−  
will be more pronounced in application with high LDO  
supply voltages (either EXTV or V ) and higher  
CC  
IN  
frequencies.  
3. Other “hidden” losses such as transition loss and cop-  
per trace and internal load resistances can account for  
additional efficiency degradations in the overall power  
system. It is very important to include these “system”  
level losses in the design of a system. Transition loss  
arises from the brief amount of time the top power  
MOSFET spends in the saturated region during switch  
node transitions. The LTC3649 internal power devices  
switch quickly enough that these losses are not signifi-  
cantcomparedtoothersources. Otherlossesincluding  
In the case where the EXTV pin is connected to the OUT  
CC  
pin, the V current will be minimal as most of the current  
IN  
used to bias up internal circuitry and gate drive will come  
directlyfromEXTV . Typicallyfora1MHzapplication, the  
CC  
current drawn from EXTV will be 20mA.  
CC  
Therefore, the total power dissipated by the part is:  
2
P = I  
• R + V • I  
EXTVCC EXTVCC  
D
OUT  
SW  
2
= 16A • 5ꢀ.25mΩ + 3.3V • 20mA  
= 99ꢀmW  
3649fb  
17  
For more information www.linear.com/LTC3649  
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