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AD8132ARMZ-REEL7 参数 Datasheet PDF下载

AD8132ARMZ-REEL7图片预览
型号: AD8132ARMZ-REEL7
PDF下载: 下载PDF文件 查看货源
内容描述: 低成本,高速差分放大器 [Low Cost, High Speed Differential Amplifier]
分类和应用: 放大器
文件页数/大小: 32 页 / 441 K
品牌: ADI [ ADI ]
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AD8132  
THEORY OF OPERATION  
The AD8132 differs from conventional op amps by the external  
presence of an additional input and output. The additional input,  
VOCM, controls the output common-mode voltage. The additional  
output is the analog complement of the single output of a conven-  
tional op amp. For its operation, the AD8132 uses two feedback  
loops as compared to the single loop of conventional op amps.  
Although this provides significant freedom to create various  
novel circuits, basic op amp theory can still be used to analyze  
the operation.  
For each feedback network, a feedback factor can be defined as  
the fraction of the output signal that is fed back to the opposite  
sign input. These terms are  
β1 = RG1  
β2 = RG2  
(
(
RG1 + RF1  
)
)
RG2 + RF2  
The feedback factor, β1, is for the side that is driven, and the  
feedback factor, β2, is for the side that is tied to a reference voltage  
(ground). Note that each feedback factor can vary anywhere  
between 0 and 1.  
One of the feedback loops controls the output common-mode  
voltage, VOUT, cm. Its input is VOCM (Pin 2) and the output is the  
common-mode, or average voltage, of the two differential outputs  
(+OUT and −OUT). The gain of this circuit is internally set to  
unity. When the AD8132 is operating in its linear region, this  
A single-ended-to-differential gain equation can be derived  
(this is true for all values of β1 and β2):  
2
(
1β1  
)
)
G =  
establishes one of the operational constraints: VOUT, cm = VOCM  
.
(
β1 + β2  
The second feedback loop controls the differential operation.  
Similar to an op amp, the gain and gain shaping of the transfer  
function can be controlled by adding passive feedback networks.  
However, only one feedback network is required to close the  
loop and fully constrain the operation, but depending on the  
function desired, two feedback networks can be used. This is  
possible because there are two outputs that are each inverted  
with respect to the differential inputs.  
This expression is not very intuitive, but some further examples can  
provide better understanding of its implications. One observation  
that can be made immediately is that a tolerance error in β1 does  
not have the same effect on gain as the same tolerance error in β2.  
DIFFERENTIAL AMPLIFIER WITHOUT RESISTORS  
(HIGH INPUT IMPEDANCE INVERTING AMPLIFIER)  
The simplest closed-loop circuit that can be made does not  
require any resistors and is shown in Figure 70. In this circuit,  
β1 is equal to 0, and β2 is equal to 1. The gain is equal to 2.  
GENERAL USAGE OF THE AD8132  
Several assumptions are made here for a first-order analysis; they  
are the typical assumptions used for the analysis of op amps:  
A more intuitive method to figure the gain is by simple inspection.  
+OUT is connected to −IN, whose voltage is equal to the voltage at  
+IN under equilibrium conditions. Thus, +VOUT is equal to VIN,  
and there is unity gain in this path. Because −OUT has to swing  
in the opposite direction from +OUT due to the common-mode  
constraint, its effect doubles the output signal and produces a  
gain of 2.  
The input bias currents are sufficiently small so they can  
be neglected.  
The output impedances are arbitrarily low.  
The open-loop gain is arbitrarily large, and drives the  
amplifier to a state where the input differential voltage is  
effectively 0.  
One useful function that this circuit provides is a high input  
impedance inverter. If +OUT is ignored, there is a unity-gain,  
high input impedance amplifier formed from +IN to −OUT.  
Most traditional op amp inverters have relatively low input  
impedances, unless they are buffered with another amplifier.  
Offset voltages are assumed to be 0.  
Though it is possible to operate the AD8132 with a purely  
differential input, many of its applications call for a circuit  
that has a single-ended input with a differential output.  
VOCM is assumed to be at midsupply. Because there is still the  
constraint that +VOUT must equal VIN, changing the VOCM voltage  
does not change +VOUT (equal to VIN). Therefore, the effect of  
changing VOCM must show up at −OUT.  
For a single-ended-to-differential circuit, the RG of the input  
that is not driven is tied to a reference voltage. This is ground.  
Other conditions are discussed in the following sections. In  
addition, the voltage at VOCM, and therefore VOUT, cm, is assumed  
to be ground. Figure 67 shows a generalized schematic of such a  
circuit using an AD8132 with two feedback paths.  
For example, if VOCM is raised by 1 V, then −VOUT must increase  
by 2 V. This makes VOUT, cm also increase by 1 V, because it is defined  
as the average of the two differential output voltages. This means  
that the gain from VOCM to the differential output is 2.  
Rev. F | Page 21 of 32  
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