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PM4100APD 参数 Datasheet PDF下载

PM4100APD图片预览
型号: PM4100APD
PDF下载: 下载PDF文件 查看货源
内容描述: 电能表评估模块 [Energy Meter Evaluation Module]
分类和应用:
文件页数/大小: 14 页 / 645 K
品牌: SAMES [ SAMES ]
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PM4100APD  
ssaammeess  
CURRENTSENSEINPUT  
The capacitor C1 is inserted to compensate for the phase shift  
caused by the current transformer. The following equation  
shows how to calculate the capacitor value for a phase shift of  
0.18degrees.  
Resistors R2 and R3 (figure 3 and figure 4) define the current  
level into the current sense inputs of the device. The  
PM4100APD module can be configured to use any type of  
shunt or CT, but to ensure proper current sensing it is advisable  
to use a shunt or CT that will give a voltage drop of at least 20mV  
at maximum supply current. The resistor values are calculated  
for an input of 16µARMS on the current sense inputs at rated  
conditions. Thedesignequationisasfollows:  
C=1/(2x p xMainsfrequencyxR8xtan(Phaseshiftangle))  
C=1/(2x p x50x1Mxtan(0.18degrees))  
C=1.013µF  
CTswithalowphaseisrecommended.  
R2=R3=(IL /16µA)xRSH /2 SHUNT Sensing  
REFERENCE VOLTAGE  
IL=Linecurrent  
The on chip reference current is determined from a biasing  
resistor R4 connected between pin 3 of the device and VSS.  
This is 47kW for the SA2102D and SA4102A, and 24kW for the  
restofthedevicescompatiblewiththismodule.  
RSH =Shuntvalue  
CON2  
GND  
3
2
1
ANALOGGROUND(GND)  
R2  
R3  
CURRENT  
IIN  
IIP  
The GND pin of the device is connected to the analog ground  
plane, whichishalfwaybetweenVDD andVSS.  
Figure 3: Current sensing using a shunt  
SENSING METHOD (CT OR SHUNT)  
Provision is made for the use of either a Current Transformer  
(CT) or a Shunt on the application module. For use with a CT,  
the terminating resistor (R1) and phase compensation  
capacitor (C1), as well as jumper (J1) must be inserted. The  
jumper references one side of the CT to ground for sensing.  
When using a CT the current sensing resistors (R2 and R3)  
mustbeinsertedaccordingtotheequationstatedbelow.  
R2=R3=(I /2500/16µA)xR1/2  
L
CT Sensing  
IL=Linecurrent  
1:2500=CTratio  
J1  
CT  
CON2  
GND  
3
2
1
R1  
R2  
R3  
CURRENT  
IIN  
IIP  
Figure 4: Current sensing using a CT  
3/14  
http://www.sames.co.za  
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