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UCC28180 参数 Datasheet PDF下载

UCC28180图片预览
型号: UCC28180
PDF下载: 下载PDF文件 查看货源
内容描述: 可编程频率,连续导通模式( CCM )升压功率因数校正(PFC )控制器 [Programmable Frequency, Continuous Conduction Mode (CCM), Boost Power Factor Correction (PFC) Controller]
分类和应用: 功率因数校正控制器
文件页数/大小: 48 页 / 1765 K
品牌: TI [ TEXAS INSTRUMENTS ]
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UCC28180  
www.ti.com  
SLUSBQ5A NOVEMBER 2013REVISED NOVEMBER 2013  
Boost Inductor  
Based upon the allowable inductor ripple current discussed above, the boost inductor, LBST, is selected after  
determining the maximum inductor peak current, IL_PEAK  
:
IRIPPLE  
+
IL _ PEAK(max) = I  
IN(max)  
2
(26)  
(27)  
2.575 A  
2
IL _ PEAK(max) = 6.436 A +  
= 7.724 A  
The minimum value of the boost inductor is calculated based upon the acceptable ripple current, IRIPPLE, at a  
worst case duty cycle of 0.5:  
VOUTD(1- D)  
LBST(min)  
³
fSWIRIPPLE  
(28)  
(29)  
390 V ´0.5(1- 0.5)  
118kHz
´
2.575 A  
LBST(min)  
³
³ 321mH  
The recommended minimum value for the boost inductor assuming a 40% ripple current is 321 µH; the actual  
value of the boost inductor that will be used is 327 µH. With this actual value used, the actual resultant inductor  
current ripple will be:  
LBST = 327mH  
(30)  
VOUTD(1- D)  
IRIPPLE(actual)  
=
fSWLBST  
(31)  
390 V ´0.5(1- 0.5)  
118kHz ´327mH  
IRIPPLE(actual)  
=
= 2.527 A  
(32)  
(33)  
2.527 A  
IL _ PEAK(max) = 6.436 A +  
= 7.7 A  
2
The duty cycle is a function of the rectified input voltage and will be continuously changing over the half line  
cycle. The duty cycle, DUTY(max), can be calculated at the peak of the minimum input voltage:  
VOUT - V  
=
IN_ RECTIFIED(min)  
DUTY  
(max)  
VOUT  
(34)  
(35)  
V
=
2 ´85 V = 120 V  
IN_ RECTIFIED(min)  
390 V -120 V  
DUTY  
=
= 0.692  
(max)  
390 V  
(36)  
Boost Diode  
The diode losses are estimated based upon the forward voltage drop, VF, at 125°C and the reverse recovery  
charge, QRR, of the diode. Using a silicon carbide Schottky diode, although more expensive, will essentially  
eliminate the reverse recovery losses and result in less power dissipation:  
PDIODE = VF _125CIOUT(max) + 0.5fSW VOUTQRR  
(37)  
(38)  
(39)  
VF _125°C = 1V  
QRR = 0nC  
PDIODE = 1V ´0.923 A + 0.5 ´119kHz ´390 V ´0nC = 0.923W  
)
(
) (  
(40)  
This output diode should have a blocking voltage that exceeds the output over voltage of the converter and be  
attached to an appropriately sized heat sink.  
Copyright © 2013, Texas Instruments Incorporated  
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