Philips Semiconductors
Product specification
LIN transceiver
TJA1020
SYMBOL
PARAMETER
CONDITIONS
MIN.
TYP.
MAX.
22.5
UNIT
tf(slope)(norm)(dom) normal slope fall time LIN normal slope mode;
−
12
12
0
µs
(100% to 0%)
CL = 6.8 nF;RL = 660 Ω;
BAT = 12 V; transition
from recessive to
dominant; note 4
V
tr(slope)(norm)(rec)
normal slope rise time
LIN (0% to 100%)
normal slope mode;
CL = 6.8 nF;RL = 660 Ω;
VBAT = 12 V; transition
from dominant to
−
22.5
+4
µs
µs
recessive; note 5
∆tslope(norm)
normal slope symmetry
normal slope mode;
CL = 6.8 nF;RL = 660 Ω;
VBAT = 12 V;
−4
t
f(slope)(dom) − tr(slope)(rec)
tf(slope)(low)(dom)
low slope fall time LIN
(100% to 0%)
low slope mode;
CL = 10 nF; RL = 500 Ω;
VBAT = 12 V; note 4
−
−
30
30
62
62
µs
µs
tr(slope)(low)(rec)
low slope rise time LIN
(0% to 100%)
low slope mode;
CL = 10 nF; RL = 500 Ω;
VBAT = 12 V; note 5
tBUS
dominant time for
wake-up via bus
sleep mode
30
7
70
20
5
150
50
µs
µs
µs
tNWAKE
tgotonorm
dominant time for
wake-up via pin NWAKE
sleep mode
time period for mode
change from sleep or
standby mode into
2
10
normal/low slope mode
tgotosleep
time period for mode
change from normal/low
slope mode into sleep
mode
2
6
5
10
20
µs
tdom
TXD dominant time out
VTXD = 0 V
12
ms
Notes
1. All parameters are guaranteed over the virtual junction temperature by design, but only 100% tested at 125 °C
ambient temperature for dies on wafer level and above this for cased products 100% tested at 25 °C ambient
temperature, unless otherwise specified.
2. For bare die, all parameters are only guaranteed if the backside of the bare die is connected to ground.
3. If VBAT is higher than 12 V, the battery current increases due to the internal LIN termination resistor. The minimum
VBAT – 12 V
-------------------------------
20 kΩ
value of this resistor is 20 kΩ. The maximum current increase is therefore: IBAT(increase)
=
((tVLIN = 40%) – (tVLIN = 95%))
4. t f(slope)(dom)
=
; see Fig.6
------------------------------------------------------------------------------------
0.55
((tVLIN = 60%) – (tVLIN = 5%))
5. t r(slope)(rec)
=
; see Fig.6
---------------------------------------------------------------------------------
0.55
2002 Jul 17
13