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MIC4423CN 参数 Datasheet PDF下载

MIC4423CN图片预览
型号: MIC4423CN
PDF下载: 下载PDF文件 查看货源
内容描述: 双路3A峰值低侧MOSFET驱动器双极/ CMOS / DMOS工艺 [Dual 3A-Peak Low-Side MOSFET Driver Bipolar/CMOS/DMOS Process]
分类和应用: 驱动器接口集成电路光电二极管
文件页数/大小: 12 页 / 120 K
品牌: MICREL [ MICREL SEMICONDUCTOR ]
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MIC4423/4424/4425  
Micrel  
in estimating power dissipation in the driver. Operating on resistance of the driver when its output is in the high state,  
frequency, power supply voltage, and load all affect power or its on resistance when the driver is in the low state,  
dissipation.  
depending on how the inductor is connected, and this is still  
only half the story. For the part of the cycle when the inductor  
is forcing current through the driver, dissipation is best  
described as  
Given the power dissipation in the device, and the thermal  
resistance of the package, junction operating temperature for  
any ambient is easy to calculate. For example, the thermal  
resistanceofthe8-pinplasticDIPpackage,fromthedatasheet,  
is 150°C/W. In a 25°C ambient, then, using a maximum  
junction temperature of 150°C, this package will dissipate  
960mW.  
P
L2  
= I V (1 – D)  
D
where V is the forward drop of the clamp diode in the driver  
D
(generally around 0.7V). The two parts of the load dissipation  
must be summed in to produce P  
L
Accurate power dissipation numbers can be obtained by  
summingthethreesourcesofpowerdissipationinthedevice:  
P = P + P  
L2  
L
L1  
Quiescent Power Dissipation  
• Load power dissipation (P )  
• Quiescent power dissipation (P )  
L
Quiescent power dissipation (P , as described in the input  
Q
Q
section) depends on whether the input is high or low. A low  
input will result in a maximum current drain (per driver) of  
0.2mA; a logic high will result in a current drain of 2.0mA.  
Quiescent power can therefore be found from:  
• Transition power dissipation (P )  
T
Calculation of load power dissipation differs depending on  
whether the load is capacitive, resistive or inductive.  
Resistive Load Power Dissipation  
P = V [D I + (1 – D) I ]  
Q
S
H
L
Dissipation caused by a resistive load can be calculated as:  
2
where:  
P = I R D  
L
O
I = quiescent current with input high  
H
where:  
I = quiescent current with input low  
L
D = fraction of time input is high (duty cycle)  
V = power supply voltage  
S
I = the current drawn by the load  
R
= the output resistance of the driver when the  
output is high, at the power supply voltage used  
(See characteristic curves)  
O
Transition Power Dissipation  
Transitionpowerisdissipatedinthedrivereachtimeitsoutput  
changes state, because during the transition, for a very brief  
interval, both the N- and P-channel MOSFETs in the output  
totem-poleareONsimultaneously,andacurrentisconducted  
D = fraction of time the load is conducting (duty cycle)  
Capacitive Load Power Dissipation  
Dissipation caused by a capacitive load is simply the energy  
placedin,orremovedfrom,theloadcapacitancebythedriver.  
The energy stored in a capacitor is described by the equation:  
through them from V to ground. The transition power  
S
dissipation is approximately:  
P = f V (A•s)  
T
S
2
E = 1/2 C V  
where (A•s) is a time-current factor derived from Figure 2.  
Asthisenergyislostinthedrivereachtimetheloadischarged  
or discharged, for power dissipation calculations the 1/2 is Total power (PD) then, as previously described is just  
removed. This equation also shows that it is good practice not  
P = P + P +P  
T
D
L
Q
to place more voltage in the capacitor than is necessary, as  
dissipation increases as the square of the voltage applied to  
the capacitor. For a driver with a capacitive load:  
Examples show the relative magnitude for each term.  
EXAMPLE 1: A MIC4423 operating on a 12V supply driving  
two capacitive loads of 3000pF each, operating at 250kHz,  
with a duty cycle of 50%, in a maximum ambient of 60°C.  
2
P = f C (V )  
L
S
where:  
First calculate load power loss:  
2
f = Operating Frequency  
C = Load Capacitance  
V = Driver Supply Voltage  
S
P = f x C x (V )  
L
S
–9  
–9  
2
P = 250,000 x (3 x 10 + 3 x 10 ) x 12  
L
= 0.2160W  
Inductive Load Power Dissipation  
Then transition power loss:  
P = f x V x (A•s)  
For inductive loads the situation is more complicated. For the  
part of the cycle in which the driver is actively forcing current  
into the inductor, the situation is the same as it is in the  
resistive case:  
T
S
–9  
= 250,000 • 12 • 2.2 x 10 = 6.6mW  
Then quiescent power loss:  
= V x [D x I + (1 – D) x I ]  
2
P
L1  
= I R  
D
O
P
Q
S
H
L
However, in this instance the R required may be either the  
O
January 1999  
9
MIC4423/4424/4425  
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