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MAX1632EAI 参数 Datasheet PDF下载

MAX1632EAI图片预览
型号: MAX1632EAI
PDF下载: 下载PDF文件 查看货源
内容描述: 多路输出,低噪声电源控制器,用于笔记本电脑 [Multi-Output, Low-Noise Power-Supply Controllers for Notebook Computers]
分类和应用: 稳压器开关式稳压器或控制器电源电路开关式控制器光电二极管电脑信息通信管理
文件页数/大小: 28 页 / 240 K
品牌: MAXIM [ MAXIM INTEGRATED PRODUCTS ]
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Mu lt i-Ou t p u t , Lo w -No is e P o w e r-S u p p ly  
Co n t ro lle rs fo r No t e b o o k Co m p u t e rs  
Table 5. Low-Voltage Troubleshooting Chart  
SYMPTOM  
CONDITION  
ROOT CAUSE  
SOLUTION  
Increase bulk output capacitance  
per formula (see Low-Voltage  
Operation section). Reduce inductor  
value.  
Sag or droop in V  
step-load change  
under  
Low V -V  
differential, <1.5V  
Limited inductor-current  
slew rate per cycle.  
OUT  
IN OUT  
Dropout voltage is too high  
(V follows V as V  
decreases)  
Reduce operation to 200kHz.  
Reduce MOSFET on-resistance and  
coil DCR.  
Low V -V  
differential, <1V  
Maximum duty-cycle limits  
exceeded.  
IN OUT  
OUT  
IN  
IN  
Unstablejitters between  
different duty factors and  
frequencies  
Low V -V  
differential, <0.5V  
Normal function of internal  
low-dropout circuitry.  
Increase the minimum input voltage  
or ignore.  
IN OUT  
Not enough duty cycle left  
to initiate forward-mode  
operation. Small AC current  
in primary cant store ener-  
gy for flyback operation.  
Reduce operation to 200kHz.  
Reduce secondary impedances;  
use a Schottky diode, if possible.  
Stack secondary winding on the  
main output.  
Low V -V  
IN OUT  
Secondary output wont  
support a load  
differential,  
< 1.3 x V  
V
(main)  
OUT  
IN  
0–MAX1635  
VL linear regulator is going  
into dropout and isnt provid-  
ing good gate-drive levels.  
Use a small 20mA Schottky diode  
for boost diode D2. Supply VL from  
an external source.  
Poor efficiency  
Low input voltage, <5V  
Low input voltage, <4.5V  
Wont start under load or  
quits before battery is  
completely dead  
Supply VL from an external source  
other than V , such as the system  
IN  
+5V supply.  
VL output is so low that it  
hits the VL UVLO threshold.  
where R  
is the DC resistance of the coil, R  
is  
DC  
DS(ON)  
________________Ap p lic a t io n s In fo rm a t io n  
the MOSFET on-resistance, and R  
is the current-  
SENSE  
He a vy-Lo a d Effic ie n c y Co n s id e ra t io n s  
The major efficiency-loss mechanisms under loads are,  
in the usual order of importance:  
sense resistor value. The R  
term assumes identi-  
DS(ON)  
cal MOSFETs for the high-side and low-side switches,  
because they time-share the inductor current. If the  
MOSFETs arent identical, their losses can be estimat-  
ed by averaging the losses according to duty factor.  
P(I2R) = I2R losses  
P(tran) = transition losses  
P(gate) = gate-charge losses  
P(diode) = diode-conduction losses  
P(cap) = capacitor ESR losses  
3
PD(tran) = transition loss = V x I  
x f x  
x
IN LOAD  
2
(V x C  
/ I  
) + 20ns  
[
]
IN  
RSS GATE  
where C  
is the reverse transfer capacitance of the  
RSS  
P(IC) = losses due to the ICs operating supply  
high-side MOSFET (a data-sheet parameter), I  
DH gate-driver peak output current (1.5A typical), and  
20ns is the rise/fall time of the DH driver (20ns typical).  
is the  
GATE  
supply current  
Ind uc tor c ore los s e s a re fa irly low a t he a vy loa d s  
because the inductors AC current component is small.  
Therefore, they arent accounted for in this analysis.  
Ferrite cores are preferred, especially at 300kHz, but  
powdered cores, such as Kool-Mu, can work well.  
P(gate) = qG x f x VL  
where VL is the internal-logic-supply voltage (+5V), and qG  
is the sum of the gate-charge values for low-side and high-  
side switches. For matched MOSFETs, qG is twice the  
Efficiency = P  
/ P x 100%  
IN  
data-sheet value of an individual MOSFET. If V  
is set to  
OUT  
OUT  
less than 4.5V, replace VL in this equation with V  
this case, efficiency can be improved by connecting VL to  
an efficient 5V source, such as the system +5V supply.  
. In  
BATT  
= P  
/ (P  
+ P  
) x 100%  
OUT  
OUT  
TOTAL  
2
P
= P(I R) + P(tran) + P(gate) +  
TOTAL  
P(diode) + P(cap) + P(IC)  
P(diode) = diode - conduction losses  
2
2
P = (I R) = (I  
) x (R  
+ R  
+ R  
)
= I  
x V  
x t x f  
LOAD  
DC  
DS(ON)  
SENSE  
LOAD  
FWD D  
22 ______________________________________________________________________________________  
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