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LM1117DTX-ADJ 参数 Datasheet PDF下载

LM1117DTX-ADJ图片预览
型号: LM1117DTX-ADJ
PDF下载: 下载PDF文件 查看货源
内容描述: 800毫安低压差线性稳压器 [800mA Low-Dropout Linear Regulator]
分类和应用: 稳压器
文件页数/大小: 25 页 / 458 K
品牌: TI [ TEXAS INSTRUMENTS ]
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LM1117/LM1117I  
10091915  
FIGURE 4. Regulator with Protection Diode  
5.0 HEATSINK REQUIREMENTS  
When an integrated circuit operates with an appreciable current, its junction temperature is elevated. It is important to quantify its  
thermal limits in order to achieve acceptable performance and reliability. This limit is determined by summing the individual parts  
consisting of a series of temperature rises from the semiconductor junction to the operating environment. A one-dimensional steady-  
state model of conduction heat transfer is demonstrated in Figure 5. The heat generated at the device junction flows through the  
die to the die attach pad, through the lead frame to the surrounding case material, to the printed circuit board, and eventually to  
the ambient environment. Below is a list of variables that may affect the thermal resistance and in turn the need for a heatsink.  
θ
θ
R JC (Component  
R CA (Application  
Variables)  
Variables)  
Leadframe Size & Material Mounting Pad Size,  
Material, & Location  
No. of Conduction Pins  
Die Size  
Placement of Mounting Pad  
PCB Size & Material  
Traces Length & Width  
Adjacent Heat Sources  
Die Attach Material  
Molding Compound Size  
and Material  
Volume of Air  
Ambient Temperatue  
Shape of Mounting Pad  
10091937  
FIGURE 5. Cross-sectional view of Integrated Circuit Mounted on a printed circuit board. Note that the case temperature  
is measured at the point where the leads contact with the mounting pad surface  
The LM1117 regulators have internal thermal shutdown to protect the device from over-heating. Under all possible operating  
conditions, the junction temperature of the LM1117 must be within the range of 0°C to 125°C. A heatsink may be required depending  
on the maximum power dissipation and maximum ambient temperature of the application. To determine if a heatsink is needed,  
the power dissipated by the regulator, PD , must be calculated:  
IIN = IL + IG  
PD = (VIN-VOUT)I L + VINIG  
Figure 6 shows the voltages and currents which are present in the circuit.  
Copyright © 1999-2012, Texas Instruments Incorporated  
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