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COM20020-5 参数 Datasheet PDF下载

COM20020-5图片预览
型号: COM20020-5
PDF下载: 下载PDF文件 查看货源
内容描述: 通用局域网控制器2K ×8板载RAM [Universal Local Area Network Controller with 2K x 8 On-Board RAM]
分类和应用: 控制器局域网
文件页数/大小: 58 页 / 248 K
品牌: SMSC [ SMSC CORPORATION ]
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If the device is configured to handle both long  
and short packets (see "Define Configuration"  
command), then receive pages should always  
be 512 bytes long because the user never  
knows what the length of the receive packet will  
be. In this case, the transmit pages may be  
made 256 bytes long, leaving at least 512 bytes  
free at any given time. Even if the Command  
Chaining operation is being used, 512 bytes is  
still guaranteed to be free because Command  
Chaining only requires two pages for transmit  
and two for receive (in this case, two 256 byte  
pages for transmit and two 512 byte pages for  
receive, leaving 512 bytes free). Please note  
that it is the responsibility of software to reserve  
512 bytes for each receive page if the device is  
The pointer may now be read to determine  
how many transfers were completed.  
·
The software flow for controlling the  
Configuration, Node ID, Tentative ID, and Next  
ID registers is generally limited to the  
initialization sequence and the maintenance of  
the network map.  
Additionally, it is necessary to understand the  
details of how the other Internal Registers are  
used in the transmit and receive sequences and  
to know how the internal RAM buffer is properly  
set up. The sequence of events that tie these  
actions together is discussed as follows.  
configured to handle long packets.  
The  
Selecting RAM Page Size  
COM20020-5 does not check page boundaries  
during reception.  
During normal operation, the 2K x 8 of RAM is  
divided into four pages of 512 bytes each. The  
page to be used is specified in the "Enable  
Transmit (Receive) from (to) Page fnn"  
command, where "nn" specifies page 0, 1, 2, or  
3. This allows the user to have constant control  
over the allocation of RAM.  
If the device is configured to handle only short  
packets, then both transmit and receive pages  
may be allocated as 256 bytes long, freeing at  
least 1KByte at any given time.  
Even if the Command Chaining operation is  
being used, 1KByte is still guaranteed to be free  
because Command Chaining only requires two  
pages for transmit and two for receive (in this  
case, a total of four 256 byte pages, leaving 1K  
free).  
When the Offset bit "f" (bit 5 of the "Enable  
Transmit (Receive) from (to) Page fnn"  
command word) is set to logic "1", an offset of  
256 bytes is added to the page specified. For  
example: to transmit from the second half of  
page 0, the command "Enable Transmit from  
Page fnn" (fnn=100 in this case) is issued by  
writing 0010 0011 to the Command Register.  
This allows a finer resolution of the buffer pages  
without affecting software compatibility. This  
scheme is useful for applications which  
frequently use packet sizes of 256 bytes or less,  
especially for microcontroller systems with  
The general rule which may be applied to  
determine where in RAM a page begins is as  
follows:  
Address = (nn x 512) + (f x 256).  
Transmit Sequence  
During a transmit sequence, the microcontroller  
selects a 256 or 512 byte segment of the RAM  
buffer and writes into it. The appropriate buffer  
size is specified in the "Define Configuration"  
command. When long packets are enabled, the  
COM20020-5 interprets the packet as either a  
long or short packet, depending on whether the  
limited memory capacity.  
The remaining  
portions of the buffer pages which are not  
allocated for current transmit or receive packets  
may be used as temporary storage for previous  
network data, packets to be sent later, or as  
extra memory for the system, which may be  
indirectly accessed.  
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