ST7669V
SET V0 with temperature compensation (Temperature ≠ 24℃)
There are 16-line slope in each temperature steps and customer can select one line slope of temperature
compensation coefficient for each temperature step. Each temperature step is 8oC. Please see Figure 7.3-5 as below.
Figure 7.3-5
In command TEMPSET each MTx, where x=0, 1, 2,…, E, F, has a value between 0 and 15. MTx = 0 results in 0V
increment on V0, MTx = 1 results in Mx=5mV increment, …, MTx = 15 results in Mx=15x5mV=75mV increment. Note that
each MTx individually corresponds to a temperature interval; The relations between Mx and V0 quantity due to temperature
V0(T) are described in the equations shown as follows:
Temperature range
Equation V0(V) at temperature=T℃
-40℃ ≦ T ＜ -32℃ V0(T) = V0(T24)+ (-32-T)．M0 +( M1 + M2 + M3 + M4 + M5 + M6 + M7)．8
-32℃ ≦ T ＜ -24℃ V0(T) = V0(T24)+ (-24-T)．M1 +( M2 + M3 + M4 + M5 + M6 + M7)．8
-24℃ ≦ T ＜ -16℃ V0(T) = V0(T24)+ (-16-T)．M2 +( M3 + M4 + M5 + M6 + M7)．8
-16℃ ≦ T ＜ -8℃
-8℃ ≦ T ＜ 0℃
0℃ ≦ T ＜ 8℃
V0(T) = V0(T24)+ (-8-T)．M3 +( M4 + M5 + M6 + M7)．8
V0(T) = V0(T24)+ (0-T)．M4 +( M5 + M6 + M7)．8
V0(T) = V0(T24)+ (8-T)．M5 +( M6 + M7)．8
8℃ ≦ T ＜ 16℃
16℃ ≦ T ＜ 24℃
24℃ ≦ T ＜ 32℃
32℃ ≦ T ＜ 40℃
40℃ ≦ T ＜ 48℃
48℃ ≦ T ＜ 56℃
56℃ ≦ T ＜ 64℃
64℃ ≦ T ＜ 72℃
72℃ ≦ T ＜ 80℃
80℃ ≦ T ＜ 88℃
V0(T) = V0(T24)+ (16-T)．M6 + M7．8
V0(T) = V0(T24)+ (24-T)．M7
V0(T) = V0(T24)－(T-24)．M8
V0(T) = V0(T24)－(T-32)．M9－M8．8
V0(T) = V0(T24)－(T-40)．M10－(M9 + M8 )．8
V0(T) = V0(T24)－(T-48)．M11－(M10 + M9 + M8 )．8
V0(T) = V0(T24)－(T-56)．M12－(M11 + M10 + M9 + M8 )．8
V0(T) = V0(T24)－(T-64)．M13－(M12 + M11 + M10 + M9 + M8 )．8
V0(T) = V0(T24)－(T-72)．M14－(M13 + M12 + M11 + M10 + M9 + M8 )．8
V0(T) = V0(T24)－(T-80)．M15－( M14 + M13 + M12 + M11 + M10 + M9 + M8 )．8
Ver 1.3
49/208
6/4/2008
SITRONIX [ SITRONIX TECHNOLOGY CO., LTD. ]
