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PQ30RV2 参数 Datasheet PDF下载

PQ30RV2图片预览
型号: PQ30RV2
PDF下载: 下载PDF文件 查看货源
内容描述: 可变输出低功率损耗稳压器 [Variable Output Low Power-Loss Voltage Regulators]
分类和应用: 稳压器
文件页数/大小: 8 页 / 66 K
品牌: SHARP [ SHARP ELECTRIONIC COMPONENTS ]
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Low Power-Loss Voltage Regulators  
PQ30RV1/PQ30RV11/PQ30RV2/PQ30RV21  
ON/OFF Operation  
D2  
D1  
V
ADJ  
R
2
V
O
VIN  
1  
2●  
4●  
R
2
D2  
R1  
+
3●  
R
L
RD  
R
3
CO  
CIN  
R
1
RL  
V
ADJ  
VO’  
High : Output OFF  
Low : Output ON  
VC  
Equivalent Circuit  
in OFF-state  
¡ON/OFF operation is available by mounting externally D2 and R3.  
¡When VADJ is forcibly raised above Vref (1.25V TYP) by applying the external signal, the output is turned off (pass transistor of  
regulator is turned off). When the output is OFF, VADJ must be higher then Vref MAX., and at the same time must be lower than  
maximum rating 7V.  
In OFF-state, the load current flows to RL from VADJ through R2. Therefore the value of R2 must be as high as possible.  
¡VO'=VADJ X RL/(RL+R2)  
occurs at the load. OFF-state equivalent circuit R1 up to 10is allowed. Select as high value of RL and R2 as possible in this range.  
In some case, as output voltage is getting lower (VO<1V) , impedance of load resistance rises. In such condition, it is sometime  
impossible to obtain the minimum value of VO'. So add the dummy resistance indicated by RD in the figure to the circuit parallel to  
the load.  
An Example of ON/OFF Circuit Using the 1-chip Microcomputer Output Port (PQ30RV1)  
<Specification>  
Output port of microcomputer  
VOH (max) =0.5 V  
VOH (min) =2.4 V (IOH=0.2mA)  
MAX. rating of IOH=0.5mA  
Output should be set as follows.  
15.6V RL=52(IO=0.3A)  
From VO=1.25V (1+R2/R1) we get VO=15.6V.  
R2/R1=11.48  
Assuming that VF(max)=0.8V for D2 in case of VOH(min)=2.4V, we get VADJ=VOH(min)-VF(max)=2.4V-0.8V=1.6V. From  
Vref(max)=1.3V we get R3=0 Ω  
If R1=10k, we get R2=11.48 X R1=114.8kand IOH as follows, ingnoring RL (52 ) :  
IOH=1.6V X (R1+R2) /R1 X R2  
=1.6V X (10k+114.8k ) /10k X 114.8k =0.17mA  
Hence, IOH<0.2mA. Therefore VOH(min)is ensured.  
Next, assuming that VF(min) =0.5V for D2 in case of VOH(max), we get:  
IOH=(5V-0.5V) (R1+R2) /R1 X R2=0.49mA which is less than the rating.  
Figure 1 shows the VO-VC characteristics when R1=10k, R2=115k, R3=0 , VIN=17V, RL=52, and D1=1S2076A (Hitachi).  
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