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MAX9030 参数 Datasheet PDF下载

MAX9030图片预览
型号: MAX9030
PDF下载: 下载PDF文件 查看货源
内容描述: 低成本,超小型,单/双/四路,单电源比较器 [Low-Cost, Ultra-Small, Single/Dual/Quad Single-Supply Comparators]
分类和应用: 比较器
文件页数/大小: 11 页 / 345 K
品牌: MAXIM [ MAXIM INTEGRATED PRODUCTS ]
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Low-Cost, Ultra-Small, Single/Dual/Quad  
Single-Supply Comparators  
V
DD  
R1  
V
DD  
V
DD  
V
DD  
R2  
IN+  
IN-  
IN+  
IN-  
V
IN  
V
REF  
OUT  
OUT  
10kΩ  
V
MAX9031  
IN  
0.1µF  
V
SS  
MAX9031  
V
SS  
Figure 1. Additional Hysteresis  
Figure 2. Time Averaging of the Input Signal for Data Recovery  
1) Find the trip points of the comparator using these  
formulas:  
Board Layout and Bypassing  
Use 100nF bypass as a starting point. Minimize signal  
trace lengths to reduce stray capacitance. Minimize the  
capacitive coupling between IN- and OUT. For slow-  
moving input signals (rise-time > 1ms), use a 1nF  
capacitor between IN+ and IN-.  
V
TH  
= V  
+[((V  
REF  
- V  
)R2) / (R1 + R2)  
REF  
REF  
= V  
DD  
V
(1 - (R2 / (R1 + R2))]  
TL  
where V is the threshold voltage at which the com-  
TH  
parator switches its output from high to low as V  
IN  
Biasing for Data Recovery  
rises above the trip point. V is the threshold volt-  
TL  
Digital data is often embedded into a bandwidth and  
amplitude-limited analog path. Recovering the data can  
be difficult. Figure 2 compares the input signal to a  
time-averaged version of itself. This self-biases the  
threshold to the average input voltage for optimal noise  
margin. Even severe phase distortion is eliminated from  
the digital output signal. Be sure to choose R1 and C1  
so that:  
age at which the comparator switches its output from  
low to high as V drops below the trip point.  
IN  
2) The hysteresis band will be:  
V
HYS  
= V - V = V (R2 / (R1 + R2))  
TH TL DD  
3) In this example, let V  
= +5V and V  
= +2.5V.  
DD  
REF  
V
TH  
= 2.5V + 2.5(R2 / (R1 + R2))V  
ƒ
CAR  
>> 1 / (2πR1C1)  
and  
where ƒ  
is the fundamental carrier frequency of the  
CAR  
V
= 2.5[1 - (R2 / (R1 + R2))]  
TL  
digital data stream.  
4) Select R2. In this example, we will choose 1k.  
5) Select V . In this example, we will choose 50mV.  
HYS  
6) Solve for R1.  
V
HYS  
= V (R2 / (R1 + R2))  
DD  
0.050V = 5(1000/(R1 + 1000)) V  
where R1 100k, V = 2.525V, and V = 2.475V.  
TH  
TL  
The above-described design procedure assumes rail-  
to-rail output swing. If the output is significantly loaded,  
the results should be corrected.  
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