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MP7610 参数 Datasheet PDF下载

MP7610图片预览
型号: MP7610
PDF下载: 下载PDF文件 查看货源
内容描述: D / A转换器,输出放大器和串行数据/地址mP在控制逻辑 [D/A Converter with Output Amplifier and Serial Data/Address mP Control Logic]
分类和应用: 转换器放大器
文件页数/大小: 16 页 / 517 K
品牌: EXAR [ EXAR CORPORATION ]
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MP7610
ELECTRICAL CHARACTERISTICS (CONT’D)
Parameter
DYNAMIC PERFORMANCE
Voltage Settling from LD
to VDAC Out
1
Channel-to-Channel Crosstalk
6
Digital Feedthrough
1, 6
Power Supply Rejection Ratio
REFERENCE INPUTS
Impedance of V
REF
V
REF
Voltage1,
2
DIGITAL INPUTS
3
Logic High
Logic Low
Input Current
Input Capacitance
1
ANALOG OUTPUTS
Output Swing
Output Drive Current
Output Impedance
Output Short Circuit Current
--V
EE
+1.4
--5
R
O
I
SC
V
CC
--1.4
1
25
30
40
55
5
V
mA
W
mA
mA
mA
mA
V
IH
V
IL
I
L
C
L
2.4
0.8
±10
8
V
V
mA
pF
REF
V
REF
350
3.5
700
1.05k
6
350
1.05k
W
V
See Application Hints for Driving
the reference input
t
sd
CT
Q
PSRR
30
0.04
--70
5
50
50
ms
LSB
dB
ppm/%
ZS to FS (20 V Step)
5k, 50pF load
DC
CLK and Data to V
OUTi
DV
EE
&
DV
CC
=
±5%,
ppm of FS
Symbol
Min
25
°
C
Typ
Max
Tmin to Tmax
Min
Max
Units
Test Conditions/Comments
+FS to AGND
+FS to V
EE
--FS to AGND
--FS to V
CC
DIGITAL OUTPUTS
Output High Voltage
Output Low Voltage
POWER SUPPLIES
V
CC
Voltage
5
V
EE
Voltage
5
DV
DD
Voltage
Positive Supply Current
Negative Supply Current
Digital Supply Current
Power Dissipation
ANALOG GROUND CURRENT
Per Channel
1
DIGITAL TIMING
SPECIFICATIONS
1,4
Input Clock Pulse Width
Data Setup Time
Data Hold Time
CLK to SDO Propagation Delay
DAC Register Load Pulse Width
Preset Pulse Width
Clock Edge to Load Time
LD Falling Edge to SDO
Tri-state Enable
t
CH
, t
CL
t
DS
t
DH
t
PD
t
LD
t
PR
t
CKLD1
t
CKLD2
t
HZ1
60
15
15
40
45
65
140
0
50
ns
ns
ns
ns
ns
ns
ns
ns
I
AGND
±60
mA
See Application Notes
V
IL
= 0, V
IH
= 5.0, C
L
= 20 pF
V
CC
V
REF
+1.5 12
V
EE
--12.75
--12
DV
DD
4.5
5
I
CC
8
I
EE
15
I
DD
PD
ISS
320
12.75
--5
5.5
10
20
2
420
V
REF
+1.5 12.75
--12.75
--5
4.5
5.5
10
20
2
450
V
V
V
mA
mA
mA
mW
V
OH
V
OL
4.5
0.5
V
V
Bipolar zero
Bipolar zero
Bipolar zero
Bipolar zero
Note: t
LD
and t
CKLD2
cannot both
be min. since t
CKLD1
=t
CKLD2
+t
LD
Rev. 4.01
5