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CS5460A-BS 参数 Datasheet PDF下载

CS5460A-BS图片预览
型号: CS5460A-BS
PDF下载: 下载PDF文件 查看货源
内容描述: 单相双向功率/电能IC [Single Phase Bi-Directional Power/Energy IC]
分类和应用:
文件页数/大小: 54 页 / 879 K
品牌: CIRRUS [ CIRRUS LOGIC ]
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CS5460A  
provide for some over-range capability, the RMS  
Voltage Register and RMS Current Register is set  
to measure 0.6 when the RMS-values of the  
line-voltage and line-current levels are 250 V and  
20 A. Therefore, when the RMS registers measure  
0.6, the voltage level at the inputs will be  
0.6 x 250 mV = 150 mV. The sensor gain con-  
stants, KV and KI, are determined by demanding  
that the voltage and current channel inputs should  
be 150 mV RMS when the power line voltage and  
current are at the maximum values of 250 V and  
20 A.  
3. FUNCTIONAL DESCRIPTION  
3.1 Pulse-Rate Output  
As an alternative to reading the real energy  
through the serial port, the EOUT and EDIR pins  
provide a simple interface with which signed ener-  
gy can be accumulated. Each EOUT pulse repre-  
sents a predetermined quantity of energy. The  
quantity of energy represented in one pulse can be  
varied by adjusting the value in the Pulse-Rate  
Register. Corresponding pulses on the EDIR out-  
put pin signify that the sign of the energy is nega-  
tive. Note that these pulses are not influenced by  
the value of the Cycle-Count Register, and they  
have no reliance on the computation cycle, de-  
scribed earlier. With MCLK = 4.096 MHz, K = 1,  
the pulses will have an average frequency (in Hz)  
equal to the frequency setting in the Pulse Rate  
Register when the input signals into the voltage  
and current channels cause full-scale readings in  
the Instantaneous Voltage and Current Registers.  
When MCLK/K is not equal to 4.096 MHz, the  
pulse-rate should be scaled by a factor of  
4.096 MHz / (MCLK/K) to get the actual output  
pulse-rate.  
KV = 150 mV / 250 V = 0.0006  
KI = 150 mV / 20 A = 0.0075 Ω  
These sensor gain constants are used to calculate  
what the input voltage levels will be on the  
CS5460A inputs when the line-voltage and  
line-current are 220 V and 15 A. These values are  
VVnom and VInom.  
VVnom = KV * 220 V = 132 mV  
VInom = KI * 15 A = 112.5 mV  
The pulse rate on EOUT will be at ‘PR’ pulses per  
second (Hz) when the RMS-levels of voltage/cur-  
rent inputs are at 250 mV. When the voltage/cur-  
rent inputs are set at VVnom and VInom, the pulse  
rate needs to be ‘IR’ = 100 pulses per second. IR  
will be some percentage of PR. The percentage is  
defined by the ratios of VVnom/250 mV and  
EXAMPLE #1: For a power line with maximum rat-  
ed levels of 250 V (RMS) and 20 A (RMS), the  
pulse-frequency on the EOUT pin needs to be  
‘IR’ = 100 pulses-per-second (100 Hz) when the  
RMS-voltage and RMS-current levels on the power  
line are 220 V and 15 A respectively. To meet this  
requirement, the pulse-rate frequency (‘PR’) in the  
Pulse-Rate Register must be set accordingly.  
V
Inom/250 mV with the following formula:  
VVnom VInom  
------------------- -------------------  
PulseRate = IR = PR ⋅  
250mV 250mV  
After calibration, the first step to finding the value  
of ‘PR’ is to set the voltage and current sensor gain  
constants, KV and KI, such that there will be ac-  
ceptable voltage levels on the CS5460A inputs  
when the power line voltage and current levels are  
at the maximum values of 250 V and 20 A. KV and  
KI are needed to determine the appropriate ratios  
of the voltage/current transformers and/or shunt  
resistor values to use in the front-end voltage/cur-  
rent sensor networks.  
From this equation the value of ‘PR’ is shown as:.  
IR  
100Hz  
PR = ------------------------------------------- = ------------------------------------------------  
VVnom VInom 132mV 112.5mV  
------------------ ----------------------  
×
------------------ ------------------  
×
250mV  
250mV  
250mV 250mV  
Therefore the Pulse-Rate Register is set to  
~420.875 Hz, or 0x00349C.  
The above equation is valid when current channel  
is set to x10 gain. If current channel gain is set to  
x50, then the equation becomes:  
For a sinewave, the largest RMS value that can be  
accurately measured (without over-driving the in-  
puts) will register ~0.7071 of the maximum DC in-  
put level. Since power signals are often not  
perfectly sinusoidal in real-world situations, and to  
IR  
PR = ----------------------------------------  
VVnom VInom  
------------------ ---------------  
×
250mV 50mV  
21  
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