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3656BG 参数 Datasheet PDF下载

3656BG图片预览
型号: 3656BG
PDF下载: 下载PDF文件 查看货源
内容描述: 变压器耦合隔离放大器 [Transformer Coupled ISOLATION AMPLIFIER]
分类和应用: 变压器隔离放大器分离技术隔离技术
文件页数/大小: 17 页 / 150 K
品牌: BB [ BURR-BROWN CORPORATION ]
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Illustrative Calculations:  
Step 6  
G2 = 1 + (RX/RK) = 2.0  
The maximum input voltage is 100mV. It is desired to  
amplify the input signal for maximum accuracy. Noninverting  
output is desired.  
RX/RK = 1.0  
RX = RK  
(15)  
Input Stage:  
Step 7  
Step 1  
The resistance seen by the + input terminal of the output  
stage amplifier A2 (pin 13) is the output resistance 100kof  
the output demodulator. The resistance seen by the (–) input  
terminal of A2 (pin 14) should be matched to the resistance  
seen by the + input terminal.  
G1 max = 5V/max Input Signal = 5V 0.1V = 50V/V  
With the above gain of 50V/V, if the input ever exceeds  
100mV, it would drive the output to saturation. Therefore, it  
is good practice to allow reasonable input overrange.  
The resistance seen by pin 14 is the parallel combination of  
RX and RK.  
So, to allow for 25% input overrange without saturation at  
the output, select:  
RX || RK = 100kΩ  
(RX • RK/(RX + RK) = 100kΩ  
G1 = 40V/V  
G1 = 1 + (RF + RA) = 40  
RK/[1 +(RK/RX)] = 100kΩ  
(16)  
RF + RA = 39  
Step 2  
(13)  
Step 8  
Solving equations (15) and (16) RK = 20kand RX  
200k.  
=
RA + RF forms a voltage divider with the 100koutput  
resistance of the demodulator. To limit the voltage divider  
loading effect to no more than 5%, RA + RF should be  
chosen to be at least 2M. For most applications, the 2MΩ  
should be sufficiently large for RA + RF. Resistances greater  
than 2Mmay help decrease the loading effect, but would  
increase the offset voltage drift.  
Step 9  
The output demodulator must be loaded equal to the input  
demodulator.  
RB = RA + RF = 2MΩ  
(See equation (14) above in Step 2).  
The voltage divider with RA + RF = 2Mis 2M/(2M+  
100k) = 2/(2 + 0.1) = 95.2%, i.e., the percent loading is  
4.8%.  
Use the resistor values obtained in Steps 3, 4, 8 and 9, and  
connect the 3656 as shown in Figure 3.  
Choose RA + RF = 2MΩ  
Step 3  
(14)  
OFFSET TRIMMING  
Figure 5 shows an optional offset voltage trim circuit. It is  
important that RA + RF = RB.  
Solving equations (13) and (14)  
RA = 50kand RF = 1.95MΩ  
Step 4  
CASE 1: Input and output stages in low gain, use output  
potentiometer (R2) only. Input potentiometer (R1)  
may be disconnected. For example, unity gain  
could be obtained by setting RA = RB = 20M, RC  
= 100k, RF = 0, RX = 100k, and RK = .  
The resistances seen by the + and – input terminals of the  
input amplifier A1 should be closely matched in order to  
minimize offset voltage due to bias currents.  
CASE 2: Input stage in high gain and output stage in low  
gain, use input potentiometer (R1) only. Output  
potentiometer (R2) may be disconnected. For  
example, GT = 100 could be obtained by setting  
RC = RA || (RF + 100k)  
= 50k|| (1.95M+ 100k)  
49kΩ  
RF = 2M, RB = 2Mreturned to pin 17, RA  
20k, RX = 100k, and RK = .  
=
Output Stage:  
CASE 3: When it is necessary to perform a two-stage  
precision trim (to maintain a very small offset  
change under conditions of changing temperature  
and changing gain in A1 and A2), use step 1 to  
adjust the input stage and step 2 for the output  
stage. Carbon composition resistors are accept-  
able, but potentiometers should be stable.  
Step 5  
VOUT = VIN MAX • G1 • G2  
As discussed in Step 1, it is good practice to provide 25%  
input overrange.  
So we will calculate G2 for 10V output and 125% of the  
maximum input voltage.  
Step 1: Input stage trim (RA = RC = 20k, RI = RB = 20M.  
RX = 100k, RK = , R2 disconnected); A1 high, A2  
low gain. Adjust R1 for 0V ±5mV or desired setting  
at VOUT, pin 15.  
VOUT = (1.25 • 0.1)(G1)(G2)  
i.e., 10V = 0.125 • 40 • G2  
G2 = 10V/5V = 2V/V  
®
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3656  
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