At stall only two elements will be on, and they will be on full time.
Pc = δS ⋅ δPWM ⋅ VCE ⋅ IC
δS = 1
δPWM = 0.1
VCE = 1.6 V
IC = 25 A
Pc = 1 ⋅ 0.1 ⋅ 1.6 ⋅ 25
Pc = 4.0 W
IC
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40
Ps = δS ⋅ [Eon + Eoff] ⋅ fo ⋅
Eon = 0.004 J
Eoff = 0.006 J
fo = 20000 Hz
25
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Ps = 1 ⋅ [0.004 + 0.006] ⋅ 20000 ⋅
Ps = 125 W
40
Pd = δs ⋅ [1 – δPWM] ⋅ Vf ⋅ If
Vf = 1.3 V
IF = 25 A
Pd = 1 ⋅ [1 – 0.1] ⋅ 1.3 ⋅ 25
Pd = 29.25 W
TjIGBT = [Pc + Ps] ⋅ θjcIGBT + TC
θjcIGBT = 0.45°C/W
TC = 85° C
TjIGBT = [4 + 125] ⋅ 0.45° + 85°
TjIGBT = 143° C
10
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