Typical Performance Characteristics–ADG417
50
T
A
= +25 C
40
V
DD
= +5V
V
SS
= –5V
80
100
T
A
= +25 C
V
DD
= +5V
V
SS
= 0V
30
R
ON
–
R
ON
–
V
DD
= +12V
V
SS
= –12V
60
V
DD
= +10V
V
SS
= –10V
V
DD
= +10V
V
SS
= 0V
20
V
DD
= +15V
V
SS
= –15V
40
V
DD
= +12V
V
SS
= 0V
10
20
V
DD
= +15V
V
SS
= 0V
0
–15
0
–10
–5
0
V
S
, V
D
– Volts
5
10
15
0
5
V
S
, V
D
– Volts
10
15
Figure 1. R
ON
as a Function of V
D
(V
S
): Dual Supply Voltage
Figure 4. R
ON
as a Function of V
D
(V
S
): Single Supply
Voltage
100
50
V
DD
= +15V
V
SS
= –15V
V
L
= +5V
40
80
V
DD
= +12V
V
SS
= 0V
V
L
= +5V
30
R
ON
–
R
ON
–
+125 C
20
+85 C
+25 C
10
60
+125 C
40
+85 C
+25 C
20
0
–15
–10
–5
0
V
S
, V
D
– Volts
5
10
15
0
0
3
6
V
S
, V
D
– Volts
9
12
Figure 2. R
ON
as a Function of V
D
(V
S
) for Different
Temperatures
Figure 5. R
ON
as a Function of V
D
(V
S
) for Different
Temperatures
0.02
V
DD
= +15V
V
SS
= –15V
T
A
= +25 C
I
D
(ON)
0.006
V
DD
= +12V
V
SS
= 0V
T
A
= +25 C
I
D
(ON)
0.002
I
S
(OFF)
I
D
(OFF)
LEAKAGE CURRENT – nA
0.01
0.004
LEAKAGE CURRENT – nA
15
I
S
(OFF)
0.00
I
D
(OFF)
–0.01
0.000
–0.02
–0.002
–0.03
–15
–10
–5
0
V
S
, V
D
– Volts
5
10
–0.004
0
2
4
6
V
S
, V
D
– Volts
8
10
12
Figure 3. Leakage Currents as a Function of V
S
(V
D
)
Figure 6. Leakage Currents as a Function of V
S
(V
D
)
REV. A
–5–