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AD2S82AHP 参数 Datasheet PDF下载

AD2S82AHP图片预览
型号: AD2S82AHP
PDF下载: 下载PDF文件 查看货源
内容描述: 可变分辨率,单片分解器数字转换器 [Variable Resolution, Monolithic Resolver-to-Digital Converters]
分类和应用: 转换器位置转换器信息通信管理
文件页数/大小: 16 页 / 207 K
品牌: ADI [ ADI ]
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AD2S81A/AD2S82A  
The small signal step response is shown in Figure 8. The time  
from the step to the first peak is t1 and the t2 is the time from  
the step until the converter is settled to 1 LSB. The times t1 and  
t2 are given approximately by  
Input Acceleration[LSB/sec2]  
Error in LSBs =  
KA[sec–2  
]
100[rev/sec2] × 212  
2.7×106  
=
= 0.15LSBs or 47.5seconds of arc  
1
t1 =  
f BW  
To determine the value of KA based on the passive components  
used to define the dynamics of the converter, the following  
should be used:  
5
R
t2 =  
×
f BW 12  
4.04 × 1011  
2n R6 R4 (C4 + C5)  
K A  
=
where R = resolution, i.e., 10, 12, 14 or 16.  
OUTPUT  
POSITION  
t2  
Where n = resolution of the converter  
R4, R6 in ohms  
C5, C4 in farads  
SOURCES OF ERRORS  
Integrator Offset  
Additional inaccuracies in the conversion of the resolver signals  
will result from an offset at the input to the integrator as it will  
be treated as an error signal. This error will typically be 1 arc  
minute over the operating temperature range.  
TIME  
t1  
A description of how to adjust from zero offset is given in the  
Component Selection section and the circuit required is shown  
in Figures 1a and 1b.  
Figure 8. AD2S81A/AD2S82A Small Step Response  
The large signal step response (for steps greater than 5 degrees)  
applies when the error voltage exceeds the linear range of the  
converter.  
Differential Phase Shift  
Phase shift between the sine and cosine signals from the resolver  
is known as differential phase shift and can cause static error.  
Some differential phase shift will be present on all resolvers as a  
result of coupling. A small resolver residual voltage (quadrature  
voltage) indicates a small differential phase shift. Additional  
phase shift can be introduced if the sine channel wires and the  
cosine channel wires are treated differently. For instance, differ-  
ent cable lengths or different loads could cause differential  
phase shift.  
Typically the converter will take three times longer to reach the  
first peak for a 179 degrees step.  
In response to a velocity step, the velocity output will exhibit  
the same time response characteristics as outlined above for the  
position output.  
ACCELERATION ERROR  
A tracking converter employing a type 2 servo loop does not  
suffer any velocity lag, however, there is an additional error due  
to acceleration. This additional error can be defined using the  
acceleration constant KA of the converter.  
The additional error caused by differential phase shift on the  
input signals approximates to  
Error = 0.53 a × b arc minutes  
where a = differential phase shift (degrees).  
b = signal to reference phase shift (degrees).  
Input Acceleration  
K A  
=
Error in Output Angle  
This error can be minimized by choosing a resolver with a small  
residual voltage, ensuring that the sine and cosine signals are  
handled identically and removing the reference phase shift (see  
Connecting the Resolver section). By taking these precautions  
the extra error can be made insignificant.  
The numerator and denominator must have consistent angular  
units. For example, if KA is in sec–2, then the input acceleration  
may be specified in degrees/sec2 and the error output in degrees.  
Angular measurement may also be specified using radians, min-  
utes of arc, LSBs, etc.  
Under static operating conditions phase shift between the refer-  
ence and the signal lines alone will not theoretically affect the  
converter’s static accuracy.  
KA does not define maximum input acceleration, only the error due  
to it’s acceleration. The maximum acceleration allowable before  
the converter loses track is dependent on the angular accuracy  
requirements of the system.  
However, most resolvers exhibit a phase shift between the signal  
and the reference. This phase shift will give rise under dynamic  
conditions to an additional error defined by:  
Angular Accuracy × KA = degrees/sec2  
KA can be used to predict the output position error for a given  
input acceleration. For example for an acceleration of 100 revs/  
sec2, KA = 2.7 × 106 sec–2 and 12-bit resolution.  
Shaft Speed (rps) × Phase Shift (Degrees)  
Reference Frequency  
REV. B  
–13–