Circuit Description: continued
feedback to the VFB Comparator sets the GATE flip-flop dur- Buck Regulator Operation
ing COSC ’s charge cycle. Once the GATE flip-flop is set,
VGATE goes low and turns on the PFET. When VCS exceeds
2.4V, the CS charge sense comparator (A4) sets the VFB com-
L
Q1
VIN
parator reference to 1.25V completing the startup cycle.
R1
CIN
RLOAD
CO
D1
Lossless Short Circuit Protection
R2
The CS51033 has “Lossless” short circuit protection since
there is no current sense resistor required. When the voltage
Control
at the CS pin (the fault timing capacitor voltage ) reaches
2.5V, the fault timing circuitry is enabled. During normal
Feedback
operation the CS voltage is 2.6V. During a short circuit con-
dition or a transient condition, the output voltage moves
lower and the voltage at VFB drops. If VFB drops below
1.15V, the output of the fault comparator goes high and the
CS51033 goes into a fast discharge mode. The fault timing
capacitor, CS, discharges to 2.4V. If the VFB voltage is still
below 1.15V when the CS pin reaches 2.4V, a valid fault con-
dition has been detected. The slow discharge comparator
output goes high and enables gate G5 which sets the slow
discharge flip flop. The Vgate flip flop resets and the output
switch is turned off. The fault timing capacitor is slowly dis-
charged to 1.5V. The CS51033 then enters a normal startup
routine. If the fault is still present when the fault timing
capacitor voltage reaches 2.5V, the fast and slow discharge
cycles repeat as shown in figure 2.
Figure 3. Buck regulator block diagram.
A block diagram of a typical buck regulator is shown in
Figure 3. If we assume that the output transistor is initially
off, and the system is in discontinuous operation, the induc-
tor current IL is zero and the output voltage is at its nominal
value. The current drawn by the load is supplied by the out-
put capacitor CO . When the voltage across CO drops below
the threshold established by the feedback resistors R1 and
R2 and the reference voltage VREF, the power transistor Q1
switches on and current flows through the inductor to the
output. The inductor current rises at a rate determined by
(VIN-VOUT)/Load. The duty cycle (or “on” time) for the
CS51033 is limited to 80%. If the output voltage remains
higher than nominal during the entire COSC charge time, the
Q1 does not turn on, skipping the pulse.
If the VFB voltage is above 1.15V when CS reaches 2.4V a
fault condition is not detected, normal operation resumes
and CS charges back to 2.6V. This reduces the chance of
erroneously detecting a load transient as a fault condition.
CHARGE PUMP CIRCUIT
2.6V
S2
2.5V
S2
S1
S2
V
CS
2.4V
(Refer to the CS51033 Application Diagram)
S3
S3
S1
S1
S3
S3
An external charge pump circuit is necessary when the input
voltage is below 5V to ensure that there is sufficient gate
drive voltage for the external FET. When VIN is applied,
capacitors C1 and C2 will be charged to a diodes drop below
VIN via diodes D2 and D4, respectively. When the PFET
turns on, its drain voltage will be approximately equal to
VIN. Since the voltage across C1 can not change instanta-
neously, D2 is reverse biased and the anode voltage rises to
approximately 2*3.3V-VD2. C1 transfers some of its stored
charge C2 via D3. After several cycles there is sufficient gate
drive voltage.
1.5V
0V
0V
T
t
t
t
FAULT
START
td1
FAULT
RESTART
td2
START
NORMAL OPERATION
FAULT
V
GATE
1.25V
1.15V
V
FB
Figure 2. Voltage on start capacitor (VGS ), the gate (VGATE ), and in the
feedback loop (VFB), during startup, normal and fault conditions.
Applications Information
to 80% min. it is best to estimate the duty cycle for the vari-
ous input conditions to see that the design will work over
the complete operating range.
Designing a Power Supply with the CS51033
The duty cycle for a buck regulator operating in a continu-
ous conduction mode is given by:
Specifications
V
V
IN = 3.3V +/- 10% (i.e. 3.63V max., 2.97V min.)
OUT = 1.5V +/- 2%
VOUT + VD
IOUT = 0.3A to 3A
Output ripple voltage < 33mV.
FSW = 200kHz.
D =
VIN - VSAT
Where VSAT is Rdson × IOUT Max.
1) Duty Cycle Estimates
In this case we can assume that VD = 0.6V and VSAT = 0.6V
so the equation reduces to:
Since the maximum duty cycle, D, of the CS51033 is limited
5