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W25Q20BWZPIP 参数 Datasheet PDF下载

W25Q20BWZPIP图片预览
型号: W25Q20BWZPIP
PDF下载: 下载PDF文件 查看货源
内容描述: 具有双路和四路SPI 1.8V 2M位串行闪存 [1.8V 2M-BIT SERIAL FLASH MEMORY WITH DUAL AND QUAD SPI]
分类和应用: 闪存
文件页数/大小: 70 页 / 2014 K
品牌: WINBOND [ WINBOND ]
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W25Q20BW  
8.2.3 Instruction Set Table 2 (Read Instructions)  
BYTE 1  
(CODE)  
INSTRUCTION NAME  
BYTE 2  
BYTE 3  
BYTE 4  
BYTE 5  
BYTE 6  
Read Data  
03h  
A23-A16  
A23-A16  
A23-A16  
A23-A16  
A23-A8(2)  
A15-A8  
A15-A8  
A7-A0  
A7-A0  
(D7-D0)  
dummy  
Fast Read  
0Bh  
(D7-D0)  
Fast Read Dual Output  
Fast Read Quad Output  
Fast Read Dual I/O  
Fast Read Quad I/O  
Word Read Quad I/O(7)  
Octal Word Read Quad I/O(8)  
3Bh  
A15-A8  
A7-A0  
dummy (D7-D0, …)(1)  
dummy (D7-D0, …)(3)  
6Bh  
A15-A8  
A7-A0  
BBh  
EBh  
E7h  
A7-A0, M7-M0(2)  
(D7-D0, …)(1)  
A23-A0, M7-M0(4) (x,x,x,x, D7-D0,…)(5) (D7-D0, …)(3)  
A23-A0, M7-M0(4)  
A23-A0, M7-M0(4)  
xxxxxx, W6-W4(4)  
(x,x, D7-D0, …)(6)  
(D7-D0, …)(3)  
(D7-D0, …)(3)  
E3h  
Set Burst with Wrap  
77h  
Notes:  
1. Dual Output data  
IO0 = (D6, D4, D2, D0)  
IO1 = (D7, D5, D3, D1)  
2. Dual Input Address  
IO0 = A22, A20, A18, A16, A14, A12, A10, A8 A6, A4, A2, A0, M6, M4, M2, M0  
IO1 = A23, A21, A19, A17, A15, A13, A11, A9 A7, A5, A3, A1, M7, M5, M3, M1  
3. Quad Output Data  
IO0 = (D4, D0, …..)  
IO1 = (D5, D1, …..)  
IO2 = (D6, D2, …..)  
IO3 = (D7, D3, …..)  
4. Quad Input Address  
Set Burst with Wrap Input  
IO0 = A20, A16, A12, A8, A4, A0, M4, M0  
IO1 = A21, A17, A13, A9, A5, A1, M5, M1  
IO2 = A22, A18, A14, A10, A6, A2, M6, M2  
IO3 = A23, A19, A15, A11, A7, A3, M7, M3  
IO0 = x, x, x, x, x, x, W4, x  
IO1 = x, x, x, x, x, x, W5, x  
IO2 = x, x, x, x, x, x, W6, x  
IO3 = x, x, x, x, x, x, x,  
x
5. Fast Read Quad I/O Data  
IO0 = (x, x, x, x, D4, D0, …..)  
IO1 = (x, x, x, x, D5, D1, …..)  
IO2 = (x, x, x, x, D6, D2, …..)  
IO3 = (x, x, x, x, D7, D3, …..)  
6. Word Read Quad I/O Data  
IO0 = (x, x, D4, D0, …..)  
IO1 = (x, x, D5, D1, …..)  
IO2 = (x, x, D6, D2, …..)  
IO3 = (x, x, D7, D3, …..)  
7. The lowest address bit must be 0. ( A0 = 0 )  
8. The lowest 4 address bits must be 0. ( A0, A1, A2, A3 = 0 )  
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