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TPS54360DDA 参数 Datasheet PDF下载

TPS54360DDA图片预览
型号: TPS54360DDA
PDF下载: 下载PDF文件 查看货源
内容描述: 60 V输入, 3.5 A降压与生态modeâ ?? ¢ DC- DC转换器 [60 V Input, 3.5 A, Step Down DC-DC Converter with Eco-mode™]
分类和应用: 转换器
文件页数/大小: 43 页 / 1954 K
品牌: TI [ TEXAS INSTRUMENTS ]
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TPS54360  
www.ti.com  
SLVSBB4C AUGUST 2012REVISED OCTOBER 2012  
Undervoltage Lockout Set Point  
The Undervoltage Lockout (UVLO) can be adjusted using an external voltage divider on the EN pin of the  
TPS54360. The UVLO has two thresholds, one for power up when the input voltage is rising and one for power  
down or brown outs when the input voltage is falling. For the example design, the supply should turn on and start  
switching once the input voltage increases above 8 V (UVLO start). After the regulator starts switching, it should  
continue to do so until the input voltage falls below 6.25 V (UVLO stop).  
Programmable UVLO threshold voltages are set using the resistor divider of RUVLO1 and RUVLO2 between Vin and  
ground connected to the EN pin. Equation 2 and Equation 3 calculate the resistance values necessary. For the  
example application, a 523 kbetween Vin and EN (RUVLO1) and a 84.5 kbetween EN and ground (RUVLO2  
)
are required to produce the 8 V and 6.25 V start and stop voltages.  
V
- V  
STOP  
8 V - 6.25 V  
START  
R
=
=
= 515 kW  
UVLO1  
I
3.4 mA  
HYS  
(38)  
V
1.2 V  
8 V - 1.2 V  
ENA  
R
=
=
= 84.5 kW  
UVLO2  
V
- V  
ENA  
START  
+1.2 mA  
+ I  
1
523 kW  
R
UVLO1  
(39)  
Output Voltage and Feedback Resistors Selection  
The voltage divider of R5 and R6 sets the output voltage. For the example design, 10.2 kwas selected for R6.  
Using Equation 1, R5 is calculated as 53.5 k. The nearest standard 1% resistor is 53.6 k. Due to the input  
current of the FB pin, the current flowing through the feedback network should be greater than 1 μA to maintain  
the output voltage accuracy. This requirement is satisfied if the value of R6 is less than 800 k. Choosing higher  
resistor values decreases quiescent current and improves efficiency at low output currents but may also  
introduce noise immunity problems.  
VOUT - 0.8 V  
5 V - 0.8 V  
æ
ö
RHS = RLS  
x
= 10.2 kW x  
= 53.5 kW  
ç
÷
0.8 V  
0.8 V  
è
ø
(40)  
Compensation  
There are several methods to design compensation for DC-DC regulators. The method presented here is easy to  
calculate and ignores the effects of the slope compensation that is internal to the device. Since the slope  
compensation is ignored, the actual crossover frequency will be lower than the crossover frequency used in the  
calculations. This method assumes the crossover frequency is between the modulator pole and the ESR zero  
and the ESR zero is at least 10 times greater the modulator pole.  
To get started, the modulator pole, ƒp(mod), and the ESR zero, ƒz1 must be calculated using Equation 41 and  
Equation 42. For COUT, use a derated value of 58.3 μF. Use equations Equation 43 and Equation 44 to estimate  
a starting point for the crossover frequency, ƒco. For the example design, ƒp(mod) is 1912 Hz and ƒz(mod) is 1092  
kHz. Equation 42 is the geometric mean of the modulator pole and the ESR zero and Equation 44 is the mean of  
modulator pole and the switching frequency. Equation 43 yields 45.7 kHz and Equation 44 gives 23.9 kHz. Use  
the lower value of Equation 43 or Equation 44 for an initial crossover frequency. For this example, the target ƒco  
is 23.9 kHz.  
Next, the compensation components are calculated. A resistor in series with a capacitor is used to create a  
compensating zero. A capacitor in parallel to these two components forms the compensating pole.  
IOUT max  
(
)
3.5 A  
fP mod  
=
=
2´ p´ VOUT ´ COUT 2 ´ p ´ 5 V ´ 58.3 mF  
= 1912 Hz  
(
)
(41)  
1
1
f
=
=
= 1092 kHz  
Z mod  
(
)
2´ p´R  
´ C  
2 ´ p ´ 2.5 mW ´ 58.3 mF  
ESR  
OUT  
(42)  
(43)  
f
=
f
f
=
1912 Hz x 1092 kHz = 45.7 kHz  
co  
p(mod) x z(mod)  
f
600 kHz  
SW  
f
=
f
=
1912 Hz x  
= 23.9 kHz  
co  
p(mod) x  
2
2
(44)  
27  
Copyright © 2012, Texas Instruments Incorporated  
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Product Folder Links: TPS54360  
 
 
 
 
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