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LM2575S-5.0 参数 Datasheet PDF下载

LM2575S-5.0图片预览
型号: LM2575S-5.0
PDF下载: 下载PDF文件 查看货源
内容描述: LM1575 / LM2575 / LM2575HV SIMPLE SWITCHER 1A降压型稳压器 [LM1575/LM2575/LM2575HV SIMPLE SWITCHER 1A Step-Down Voltage Regulator]
分类和应用: 稳压器开关式稳压器或控制器电源电路开关式控制器
文件页数/大小: 44 页 / 6007 K
品牌: TI [ TEXAS INSTRUMENTS ]
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LM1575, LM2575-N, LM2575HV  
www.ti.com  
SNVS106E MAY 1999REVISED APRIL 2013  
PROCEDURE (Adjustable Output Voltage Versions)  
EXAMPLE (Adjustable Output Voltage Versions)  
Given:  
Given:  
VOUT = Regulated Output Voltage  
VIN(Max) = Maximum Input Voltage  
ILOAD(Max) = Maximum Load Current  
F = Switching Frequency (Fixed at 52 kHz)  
VOUT = 10V  
VIN(Max) = 25V  
ILOAD(Max) = 1A  
F = 52 kHz  
1. Programming Output Voltage (Selecting R1 and R2, as shown 1. Programming Output Voltage (Selecting R1 and R2)  
in Figure 25 and Figure 26)  
Use the following formula to select the appropriate resistor values.  
(1)  
(3)  
R1 can be between 1k and 5k. (For best temperature coefficient and  
stability with time, use 1% metal film resistors)  
R2 = 1k (8.13 1) = 7.13k, closest 1% value is 7.15k  
(2)  
2. Inductor Selection (L1)  
2. Inductor Selection (L1)  
A. Calculate the inductor Volt • microsecond constant,  
E • T (V • μs), from the following formula:  
A. Calculate E • T (V • μs)  
(5)  
(4)  
B. E • T = 115 V • μs  
B. Use the E • T value from the previous formula and match it with  
the E • T number on the vertical axis of the Inductor Value  
Selection Guide shown in Figure 31.  
C. ILOAD(Max) = 1A  
D. Inductance Region = H470  
E. Inductor Value = 470 μH Choose from AIE part #430-0634, Pulse  
Engineering part #PE-53118, or Renco part #RL-1961.  
C. On the horizontal axis, select the maximum load current.  
D. Identify the inductance region intersected by the E • T value and  
the maximum load current value, and note the inductor code for that  
region.  
E. Identify the inductor value from the inductor code, and select an  
appropriate inductor from the table shown in Table 2. Part numbers  
are listed for three inductor manufacturers. The inductor chosen  
must be rated for operation at the LM2575 switching frequency (52  
kHz) and for a current rating of 1.15 × ILOAD. For additional inductor  
information, see INDUCTOR SELECTION.  
3. Output Capacitor Selection (COUT  
)
3. Output Capacitor Selection (COUT  
)
A. The value of the output capacitor together with the inductor A.  
defines the dominate pole-pair of the switching regulator loop. For  
stable operation, the capacitor must satisfy the following  
requirement:  
(7)  
However, for acceptable output ripple voltage select  
C
OUT 220 μF  
(6)  
COUT = 220 μF electrolytic capacitor  
The above formula yields capacitor values between 10 μF and 2000  
μF that will satisfy the loop requirements for stable operation. But to  
achieve an acceptable output ripple voltage, (approximately 1% of  
the output voltage) and transient response, the output capacitor may  
need to be several times larger than the above formula yields.  
B. The capacitor's voltage rating should be at last 1.5 times greater  
than the output voltage. For a 10V regulator, a rating of at least 15V  
or more is recommended.  
Higher voltage electrolytic capacitors generally have lower ESR  
numbers, and for this reason it may be necessary to select a  
capacitor rate for a higher voltage than would normally be needed.  
(Continued)  
(Continued)  
Copyright © 1999–2013, Texas Instruments Incorporated  
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Product Folder Links: LM1575 LM2575-N LM2575HV