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SAN3020 参数 Datasheet PDF下载

SAN3020图片预览
型号: SAN3020
PDF下载: 下载PDF文件 查看货源
内容描述: 单芯片电话提取功率为外部负载 [SINGLE CHIP TELEPHONE POWER EXTRACTION FOR EXTERNAL LOADS]
分类和应用: 电话
文件页数/大小: 4 页 / 39 K
品牌: SAMES [ SAMES ]
 浏览型号SAN3020的Datasheet PDF文件第1页浏览型号SAN3020的Datasheet PDF文件第3页浏览型号SAN3020的Datasheet PDF文件第4页  
SAN3020  
When driving external loads by extracting power from the available line current, care must be taken not to affect  
both DC and AC impedance. The extracted voltage should be independent from line current (assuming a line  
current >20mA).  
The application shown will shut off the external load when going on-hook and power-up the load when going off-  
hook.  
The current driving capability depends on the available line current, higher line currents allow higher driving  
currents. At minimum line current (20mA), the maximum load current is 15mA (see pt.6 for further details).  
6 Hardware configuration  
Only 4 external components , shown in the dotted area (1 general purpose PNP transistor:Bmin=250, 1 general  
purpose diode , 1 resistor and 1 pol. capacitor) must be added to the standard SA253x application to get a high  
efficiency power extraction for external loads with the features described in pt.5 above.  
When updating an existing circuit, the connection from pin #25 (= CS, SA253x) to the shunt transistor’s base (in  
most applications = Q3) must be opened and a diode (D5) installed. All further components are simply added to the  
circuit.  
7 Circuit description  
The shunt transistor (Q3) is regulating the voltage at LI ( #27) to 4.5V. Consequently, the voltage at CS ( #25) is  
VLI - VBE. When adding D5, the voltage drop between LI and CS is Vconst = 2x VBE. This constant voltage provides  
the base current of the power extraction transistor Q5 via R22.  
The maximum load current also depends on the gain (B= IC / IB) of the transistor used. The transistor used should  
have a B of 250 . Transistors with lower gain may also be used, but the maximum load current may be lower.  
7.1 Minimum output voltage with high signals on line:  
As shown in the diagram (pt. 9), the output voltage at high load currents will drop with high transmit or receive  
signals on line, since the load is not supplied during the negative half-wave of the line signal. The diagram shows  
the Vout/ILoad curves with no AC signal at line and with a constant AC line signal of 1Vpeak  
.
In practical use, an AC signal of 2Vpp is not present continuously, so the effective output voltage will be higher. It is  
also possible to buffer the voltage drop during line signal bursts by increasing the value of capacitor C19.  
However, the voltage decrease with high signal bursts on line should be taken into consideration when the load  
voltage must not drop below a certain value.  
8 Connecting loads at VDD  
Small loads can also be connected at VDD directly, as long as the following rules are observed:  
1. When on-hook, the load must only draw <1µA , because it is connected in parallel to the VDD -cap, which  
maintains memory data retention in on-hook state, charged by a 5Mresistor . A higher load current would  
discharge this capacitor and erase the memory contents.  
2. The load will also be supplied in ringing mode.  
3. When off-hook, the load current can be <5mA, provided it does not exceed this current at any time.  
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