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SA2005FPA 参数 Datasheet PDF下载

SA2005FPA图片预览
型号: SA2005FPA
PDF下载: 下载PDF文件 查看货源
内容描述: 三相双向功率/电能计量IC,具有瞬时脉冲输出 [Three Phase Bidirectional Power/Energy Metering IC with Instantaneous Pulse Output]
分类和应用: 脉冲光电二极管
文件页数/大小: 10 页 / 109 K
品牌: SAMES [ SAMES ]
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SA2005F  
ssaammeess  
TYPICAL APPLICATION  
VOLTAGEDIVIDER  
In figure 5, the components required for the three phase  
power/energy metering section of a meter, is shown. The  
application uses current transformers for current sensing. The  
4-wire meter section is capable of measuring 3x230V/80A with  
precision better than Class 1.  
The voltage divider is calculated for a voltage drop of 14V.  
Equationsforthevoltagedividerinfigure5are:  
RA=R16+R19+R22  
RB=R8||(R13+P1)  
Combiningthetwoequationsgives:  
The most important external components for the SA2005F  
integrated circuit are the current sense resistors, the voltage  
sense resistors as well as the bias setting resistor.  
(RA+RB)/230V=RB/14V  
A 5k trimpot is used in each of voltage channel for meter  
calibration. The center position of the pot is used in the  
calculations. P1 = 2.5k and values for resistors R13 = 22k and  
R8=1Mischosen.  
BIAS RESISTOR  
R7 defines all on-chip and reference currents. With R7=24kW,  
optimum conditions are set. Device calibration is done on the  
voltage inputs of the device.  
Substitutingthevaluesresultin:  
RB=23.9k  
RA=RBx(230V/14V-1)  
RA=368.9k.  
CT TERMINATION RESISTOR  
The voltage drop across the CT termination resistor at rated  
current should be at least 20mV. The CTs used have low  
phase shift and a ratio of 1:2500.The CT is terminated with a  
2.7W resistor giving a voltage drop across the termination  
resistor 864mV at rated conditions (Imax for the meter).  
Resistor values of R16, R19 and R22 is chosen to be 120k,  
120kand130k.  
CURRENT SENSE RESISTORS  
The three voltage channels are identical so R14= R15= R16 =  
R17=R18=R19andR20=R21=R22.  
The resistors R1 and R2 define the current level into the  
current sense inputs of phase one of the device. The resistor  
values are selected for an input current of 16µA on the current  
inputs at rated conditions.  
According to equation described in the Current Sense inputs  
section:  
R1 = R2 = (I / 16µA ) x R / 2  
SH  
L
=80A/2500/1Ax2.7W /2  
=2.7kW  
I =Linecurrent/CTRatio  
L
The three current channels are identical so R1 = R2 = R3 = R4  
=R5=R6.  
6/10  
http://www.sames.co.za