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SA2002HSA 参数 Datasheet PDF下载

SA2002HSA图片预览
型号: SA2002HSA
PDF下载: 下载PDF文件 查看货源
内容描述: 单相双向功率/电能计量IC,具有瞬时脉冲输出 [Single Phase Bi-directional Power / Energy Metering IC with Instantaneous Pulse Output]
分类和应用: 脉冲
文件页数/大小: 12 页 / 149 K
品牌: SAMES [ SAMES ]
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SA2002H  
ssaammeess  
TYPICAL APPLICATION  
VOLTAGE DIVIDER  
In figure 11, the components required for stand alone power  
metering application, is shown. The application uses a shunt  
resistor for the mains current sensing. The meter is designed  
The voltage divider is calculated for a voltage drop of 14V +  
5%(14.7V). Equations for the voltage divider in figure 9 are:  
for 220V/40A I  
operation. The most important external  
RA = R1 + R2 + R3  
MAX  
components for the SA2002H integrated circuit are the current  
sense resistors, the voltage sense resistors as well as the bias  
setting resistor.  
RB = R12 || (R11+P1)  
Combining the two equations gives:  
(RA + RB) / 220V = RB / 14.7V  
BIAS RESISTOR  
R13 defines all on-chip and reference currents. With  
R13=24kW, optimum conditions are set. Device calibration is  
done on the voltage input of the device.  
A 5k trimpot will be used in the voltage channel for meter  
calibration. The center position on the pot is used in the  
calculations. P1 = 2.5kW and values for resistors R11 = 22kW  
and R12 =1MWis chosen.  
SHUNT RESISTOR  
The voltage drop across the shunt resistor at rated current  
should be at least 20mV. A shunt resistor with a value of 625µW  
is chosen. The voltage drop across the shunt resistor is 25mV  
at rated conditions (Imax). The power dissipation in the current  
sensor is:  
Substituting the values will result in:  
RB = 23.91kW  
RA = RB x (230V/14.7V - 1) = 333kW so the resistor values of  
R1, R2 and R3 are chosen to be 110kW.  
P=(40A)² x 625µW= 1W.  
CURRENT SENSE RESISTORS  
The resistors R6 and R7 define the current level into the  
current sense inputs of the device. The resistor values are  
selected for an input current of 16µA on the current inputs of  
the SA2002H at rated conditions. According to equation  
described in the Current Sense inputs section:  
R6 = R7 = ( I / 16µA ) x RSH / 2  
L
= 40A / 16µA x 625µW / 2  
= 781.2W  
A resistor with value of 820W is chosen, the 5% deviation from  
the calculated value will be compensated for when calculating  
resistor values for the voltage path.  
8/12  
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