欢迎访问ic37.com |
会员登录 免费注册
发布采购

LM2575HVT-5.0LB03 参数 Datasheet PDF下载

LM2575HVT-5.0LB03图片预览
型号: LM2575HVT-5.0LB03
PDF下载: 下载PDF文件 查看货源
内容描述: [IC 3.2 A SWITCHING REGULATOR, 63 kHz SWITCHING FREQ-MAX, PZFM5, TO-220, 5 PIN, Switching Regulator or Controller]
分类和应用: 局域网开关
文件页数/大小: 29 页 / 894 K
品牌: NSC [ National Semiconductor ]
 浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第12页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第13页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第14页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第15页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第17页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第18页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第19页浏览型号LM2575HVT-5.0LB03的Datasheet PDF文件第20页  
PROCEDURE (Adjustable Output Voltage Versions)  
Given:  
EXAMPLE (Adjustable Output Voltage Versions)  
Given:  
VOUT = Regulated Output Voltage  
VOUT = 10V  
VIN(Max) = Maximum Input Voltage  
ILOAD(Max) = Maximum Load Current  
F = Switching Frequency (Fixed at 52 kHz)  
VIN(Max) = 25V  
ILOAD(Max) = 1A  
F = 52 kHz  
1. Programming Output Voltage (Selecting R1 and R2, as shown 1.Programming Output Voltage (Selecting R1 and R2)  
in Figure 2 )  
Use the following formula to select the appropriate resistor values.  
R1 can be between 1k and 5k. (For best temperature coefficient and  
stability with time, use 1% metal film resistors)  
R2 = 1k (8.13 − 1) = 7.13k, closest 1% value is 7.15k  
2. Inductor Selection (L1)  
2. Inductor Selection (L1)  
A. Calculate the inductor Volt • microsecond constant,  
E • T (V • μs), from the following formula:  
A. Calculate E • T (V • μs)  
B. E • T = 115 V • μs  
C. ILOAD(Max) = 1A  
D. Inductance Region = H470  
E. Inductor Value = 470 μH Choose from AIE part #430-0634,  
Pulse Engineering part #PE-53118, or Renco part #RL-1961.  
B. Use the E • T value from the previous formula and match it with  
the E • T number on the vertical axis of the Inductor Value Selec-  
tion Guide shown in Figure 7.  
C. On the horizontal axis, select the maximum load current.  
D. Identify the inductance region intersected by the E • T value and  
the maximum load current value, and note the inductor code for that  
region.  
E. Identify the inductor value from the inductor code, and select an  
appropriate inductor from the table shown in Figure 9. Part numbers  
are listed for three inductor manufacturers. The inductor chosen  
must be rated for operation at the LM2575 switching frequency (52  
kHz) and for a current rating of 1.15 × ILOAD. For additional inductor  
information, see the inductor section in the application hints section  
of this data sheet.  
3. Output Capacitor Selection (COUT  
)
3. Output Capacitor Selection (COUT  
)
A. The value of the output capacitor together with the inductor de- A.  
fines the dominate pole-pair of the switching regulator loop. For  
stable operation, the capacitor must satisfy the following require-  
ment:  
However, for acceptable output ripple voltage select  
COUT 220 μF  
COUT = 220 μF electrolytic capacitor  
The above formula yields capacitor values between 10 μF and 2000  
μF that will satisfy the loop requirements for stable operation. But  
to achieve an acceptable output ripple voltage, (approximately 1%  
of the output voltage) and transient response, the output capacitor  
may need to be several times larger than the above formula yields.  
B. The capacitor's voltage rating should be at last 1.5 times greater  
than the output voltage. For a 10V regulator, a rating of at least 15V  
or more is recommended.  
Higher voltage electrolytic capacitors generally have lower ESR  
numbers, and for this reason it may be necessary to select a ca-  
pacitor rate for a higher voltage than would normally be needed.  
(Continued)  
(Continued)  
15  
www.national.com  
 复制成功!