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ML4875ES-5 参数 Datasheet PDF下载

ML4875ES-5图片预览
型号: ML4875ES-5
PDF下载: 下载PDF文件 查看货源
内容描述: 低电压升压稳压器,带有关断 [Low Voltage Boost Regulator with Shutdown]
分类和应用: 稳压器
文件页数/大小: 10 页 / 199 K
品牌: MICRO-LINEAR [ MICRO LINEAR CORPORATION ]
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ML4875
INPUT CAPACITOR
Unless the input source is a very low impedance battery,
it will be necessary to decouple the input with a capacitor
with a value of between 47µF and 100µF. This provides
the benefits of preventing input ripple from affecting the
ML4875 control circuitry, and it also improves efficiency
by reducing I-squared R losses during the charge and
discharge cycles of the inductor. Again, a low ESR
capacitor (such as tantalum) is recommended.
DRIVING THE SHDN INPUT
Unlike other boost regulators which use external Schottky
diodes, the ML4875 has the ability to isolate the load from
the battery input when the SHDN pin is high. Since there
may be no other voltage available when the regulator is in
shutdown, the SHDN input threshold is set well below the
minimum V
IN
voltage. SHDN can be driven directly from
an open collector device with a high value pull-up resistor
to V
IN
. If SHDN is driven from a TTL or CMOS output
device, a resistor divider should be used to prevent the
SHDN input high level from exceeding V
IN
, and to ensure
the SHDN input low level is below the 200mV threshold.
SETTING THE
RESET
THRESHOLD
To use the
RESET
comparator as an input voltage monitor,
it is necessary to use an external resistor divider tied to the
DETECT pin as shown in the block diagram. The resistor
values R
A
and R
B
can be calculated using the following
equation:
LAYOUT
Good PC board layout practices will ensure the proper
operation of the ML4875. Important layout considerations
include:
• Use adequate ground and power traces or planes
• Keep components as close as possible to the ML4875
• Use short trace lengths from the inductor to the V
L
pin
and from the output capacitor to the V
OUT
pin
• Use a single point ground for the ML4875 ground pins,
and the input and output capacitors
V
IN(MIN)
=
0.2
×
(R
A
+
R
B
)
R
B
(5)
The value of R
B
should be 100k�½ or less to minimize bias
current errors. R
A
is then found by rearranging the
equation:
V
R
A
=
R
B
× 
IN(MIN)
1
0.2
(6)
8