欢迎访问ic37.com |
会员登录 免费注册
发布采购

MAS6502 参数 Datasheet PDF下载

MAS6502图片预览
型号: MAS6502
PDF下载: 下载PDF文件 查看货源
内容描述: 压阻式传感器 [Piezoresistive Sensor]
分类和应用: 传感器
文件页数/大小: 20 页 / 291 K
品牌: MAS [ MICRO ANALOG SYSTEMS ]
 浏览型号MAS6502的Datasheet PDF文件第1页浏览型号MAS6502的Datasheet PDF文件第2页浏览型号MAS6502的Datasheet PDF文件第3页浏览型号MAS6502的Datasheet PDF文件第5页浏览型号MAS6502的Datasheet PDF文件第6页浏览型号MAS6502的Datasheet PDF文件第7页浏览型号MAS6502的Datasheet PDF文件第8页浏览型号MAS6502的Datasheet PDF文件第9页  
DA6502.008
29 November 2012
ELECTRICAL CHARACTERISTICS
T
A
= -40
o
C to +85
o
C, VDD = 2.0V to 3.6V, Typ T
A
= 27
o
C, Typ VDD = 2.35 V, R
sensor
= 4.5kΩ unless otherwise noted
Parameter
Resolution
Symbol
N
BIT
V
LSB
Conditions
OSR=512
ISR = 325 mV
ISR = 100 mV
Note 1.
OSR=512, ISR = 325 mV
OSR = 512, T
A
= 27 C
ISRLIN = 260 mV
OSR=512, VDD = 2.35V,
o
T
A
= 27 C
ISRLIN = 260 mV
ISRLIN = 100 mV
Note 2.
Pressure mode, OSR=512,
o
ISR = 325mV, T
A
= 27 C
VDD step 3.6V
2.0V
Temperature mode, OSR=512,
o
ISR = 325mV, T
A
= 27 C
VDD step 3.6V
2.0V
o
ISRLIN = 260 mV, T
A
= 27 C
OSR=512
OSR=256
OSR=128
OSR=64
Note 3.
o
Min
Typ
16
5
1.5
3.4
0.68
Max
Unit
Bit
µV
Noise (one sigma)
Accuracy
Integral Nonlinearity
V
N
µV
RMS
LSB
µV
1)
±20
INL
±2.7
±6.2
±15
±6
1)
±14
±40
LSB
VDD Sensitivity in
Pressure Mode
VDD Sensitivity in
Temperature Mode
Linearity in Bits
VDDSENSP
LSB
VDDSENST
±80
±150
LSB
LIN
14
13
12
10
325
220
150
100
260
176
120
80
33
0
0
0
0
0
6515
3239
800
195
65152
32385
8001
1953
58637
29147
7201
1758
Bit
Input Signal Range
ISR
mV
Linear Input Signal
Range
ISRLIN
10%...90% range (80%) of ISR
mV
Input Signal Offset
Output Code Values
OFFSET
CODE
Linear Range Output
Code Values
(10%...90% of Whole
Code Range)
+33mV selection
No offset selection
OSR=512
OSR=256
OSR=128
OSR=64
OSR=512
OSR=256
OSR=128
OSR=64
mV
1) Guaranteed by design
Note 1. ISR (ISRLIN) and OSR refer to the ADC control register bits, see table 2 on page 8.
Note 2. Integral nonlinearity calculated from best fit line to linear input signal range containing 21pcs analysis points
.
Note 3. Linearity in bits calculated from LIN=log(CODELIN/INL)/log(2)=log(80%*CODE
MAX
/INL)/log(2)
4 (20)