TB62710P/F/FN
The bottom figure shows an application circuit.
For best results, this IC should be operated with V = 2.0 V.
O
V
O
(V) = V
= V
− V
OUT
CC
CC
− V (LED) − V
CE1
f
When V
CC
is high and the V of the LED is low.
f
V
O
is also high , the increase in power dissipation may in turn adversely affect the IC’s output current.
In this case, reduce the voltage by connecting an external resistor.
In this way the IC’s output current can be stabilized.
V
OUT
− V − V (min)
f O
CC
(max)× BIT number (max)
R =
I
It is looked for.
it is also possible that the IC will operate in an unstable manner due to the inductance of the wiring.
To counter this, it is recommended that the IC be situated as close as possible on the PCB to the LED module, and
as far as possible from other ICs. Otherwise, there is the risk that the IC will malfunction.
Application
R
V
= 5~17 (V)
LED
V
DD
n
SCAN
V
V
CC
CC
OUT0
OUT7
ENABLE
CLOCK
LATCH
SERIAL-IN
SERIAL-OUT1,
SERIAL-OUT2
R-EXT GND
CPU
V
V
CC
CC
OUT0
OUT7
V
CE1
ENABLE
CLOCK
LATCH
SERIAL-IN
R-EXT GND
SERIAL-OUT1,
SERIAL-OUT2
V
= V
− V
− V
f (LED) CE1
O
CC
For best results, operate at V = 2.0 V
O
12
2001-04-16
MARKTECH [ MARKTECH CORPORATE ]
