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LTC1629I-PG 参数 Datasheet PDF下载

LTC1629I-PG图片预览
型号: LTC1629I-PG
PDF下载: 下载PDF文件 查看货源
内容描述: 多相,高效率,同步降压型开关稳压器 [PolyPhase, High Efficiency, Synchronous Step-Down Switching Regulators]
分类和应用: 稳压器开关
文件页数/大小: 28 页 / 332 K
品牌: Linear [ Linear ]
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LTC1629/LTC1629-PG  
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APPLICATIO S I FOR ATIO  
Efficiency Considerations  
3) I2R losses are predicted from the DC resistances of the  
fuse (if used), MOSFET, inductor, current sense resistor,  
and input and output capacitor ESR. In continuous mode  
The percent efficiency of a switching regulator is equal to  
the output power divided by the input power times 100%.  
It is often useful to analyze individual losses to determine  
what is limiting the efficiency and which change would  
produce the most improvement. Percent efficiency can be  
expressed as:  
the average output current flows through L and RSENSE  
,
but is “chopped” between the topside MOSFET and the  
synchronous MOSFET. If the two MOSFETs have approxi-  
mately the same RDS(ON), then the resistance of one  
MOSFET can simply be summed with the resistances of L,  
SENSE and ESR to obtain I2R losses. For example, if each  
%Efficiency = 100% – (L1 + L2 + L3 + ...)  
R
RDS(ON)=10m, RL=10m, and RSENSE=5m, then the  
total resistance is 25m. This results in losses ranging  
from 2% to 8% as the output current increases from 3A to  
15A per output stage for a 5V output, or a 3% to 12% loss  
per output stage for a 3.3V output. Efficiency varies as the  
inverse square of VOUT for the same external components  
and output power level. The combined effects of increas-  
ingly lower output voltages and higher currents required  
by high performance digital systems is not doubling but  
quadrupling the importance of loss terms in the switching  
regulator system!  
whereL1, L2, etc. aretheindividuallossesasapercentage  
of input power.  
Although all dissipative elements in the circuit produce  
losses, four main sources usually account for most of the  
losses in LTC1629 circuits: 1) LTC1629 VIN current (in-  
cluding loading on the differential amplifier output),  
2) INTVCC regulator current, 3) I2R losses and 4) Topside  
MOSFET transition losses.  
1) The VIN current has two components: the first is the  
DC supply current given in the Electrical Characteristics  
table, which excludes MOSFET driver and control cur-  
rents; the second is the current drawn from the differential  
amplifier output. VIN current typically results in a small  
(<0.1%) loss.  
4) Transition losses apply only to the topside MOSFET(s),  
and only when operating at high input voltages (typically  
20V or greater). Transition losses can be estimated from:  
2
Transition Loss = (1.7) VIN IO(MAX) CRSS  
f
2) INTVCC current is the sum of the MOSFET driver and  
control currents. The MOSFET driver current results from  
switching the gate capacitance of the power MOSFETs.  
Each time a MOSFET gate is switched from low to high to  
low again, a packet of charge dQ moves from INTVCC to  
ground. The resulting dQ/dt is a current out of INTVCC that  
is typically much larger than the control circuit current. In  
continuous mode, IGATECHG = (QT + QB), where QT and QB  
are the gate charges of the topside and bottom side  
MOSFETs.  
Other “hidden” losses such as copper trace and internal  
battery resistances can account for an additional 5% to  
10% efficiency degradation in portable systems. It is very  
important to include these “system” level losses in the  
design of a system. The internal battery and input fuse  
resistance losses can be minimized by making sure that  
CIN has adequate charge storage and a very low ESR at the  
switching frequency. A 50W supply will typically require a  
minimum of 200µF to 300µF of capacitance having a  
maximum of 10mto 20mof ESR. The LTC1629  
PolyPhase architecture typically halves to quarters this  
input capacitance requirement over competing solutions.  
Other losses including Schottky conduction losses during  
dead-time and inductor core losses generally account for  
less than 2% total additional loss.  
SupplyingINTVCC powerthroughtheEXTVCC switchinput  
from an output-derived source will scale the VIN current  
required for the driver and control circuits by the ratio  
(Duty Factor)/(Efficiency). For example, in a 20V to 5V  
application, 10mA of INTVCC current results in approxi-  
mately 3mA of VIN current. This reduces the mid-current  
loss from 10% or more (if the driver was powered directly  
from VIN) to only a few percent.  
20  
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