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LT1172CS8 参数 Datasheet PDF下载

LT1172CS8图片预览
型号: LT1172CS8
PDF下载: 下载PDF文件 查看货源
内容描述: 为100kHz ,5A , 2.5A和1.25A的高效率开关稳压器 [100kHz, 5A, 2.5A and 1.25A High Efficiency Switching Regulators]
分类和应用: 稳压器开关式稳压器或控制器电源电路开关式控制器光电二极管
文件页数/大小: 20 页 / 269 K
品牌: Linear [ Linear ]
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LT1170/LT1171/LT1172  
U
OPERATIO  
function; when pulled low with an external resistor, it  
programs the LT1170/LT1171/LT1172 to disconnect the  
main error amplifier output and connects the output of the  
flyback amplifier to the comparator input. The LT1170/  
LT1171/LT1172 will then regulate the value of the flyback  
pulse with respect to the supply voltage.* This flyback  
pulse is directly proportional to output voltage in the  
traditional transformer coupled flyback topology regula-  
tor. By regulating the amplitude of the flyback pulse, the  
output voltage can be regulated with no direct connection  
between input and output. The output is fully floating up to  
the breakdown voltage of the transformer windings. Mul-  
tiple floating outputs are easily obtained with additional  
windings. A special delay network inside the LT1170/  
LT1171/LT1172 ignores the leakage inductance spike at  
the leading edge of the flyback pulse to improve output  
regulation.  
when switch currents exceed 300mA. Also, note that chip  
dissipation will actually increase with E2 open during  
normal load operation, even though dissipation in current  
limit mode will decrease. See “Thermal Considerations”  
next.  
Thermal Considerations When Using the MiniDIP and  
SW Packages  
The low supply current and high switch efficiency of the  
LT1172 allow it to be used without a heat sink in most  
applications when the TO-220 or TO-3 package is se-  
lected. These packages are rated at 50°C/W and 35°C/W  
respectively.TheminiDIPs,however,areratedat100°C/W  
in ceramic (J) and 130°C/W in plastic (N).  
Care should be taken for miniDIP applications to ensure  
that the worst case input voltage and load current condi-  
tionsdonotcauseexcessivedietemperatures.Thefollow-  
ing formulas can be used as a rough guide to calculate  
LT1172 power dissipation. For more details, the reader is  
referred to Application Note 19 (AN19), “Efficiency Calcu-  
lations” section.  
The error signal developed at the comparator input is  
brought out externally. This pin (VC) has four different  
functions. It is used for frequency compensation, current  
limit adjustment, soft starting, and total regulator shut-  
down. During normal regulator operation this pin sits at a  
voltage between 0.9V (low output current) and 2.0V (high  
output current). The error amplifiers are current output  
(gm) types, so this voltage can be externally clamped for  
adjusting current limit. Likewise, a capacitor coupled  
external clamp will provide soft start. Switch duty cycle  
goes to zero if the VC pin is pulled to ground through a  
diode,placingtheLT1170/LT1171/LT1172inanidlemode.  
Pulling the VC pin below 0.15V causes total regulator  
shutdown, with only 50µA supply current for shutdown  
circuitry biasing. See AN19 for full application details.  
Average supply current (including driver current) is:  
IIN 6mA + ISW(0.004 + DC/40)  
ISW = switch current  
DC = switch duty cycle  
Switch power dissipation is given by:  
PSW = (ISW)2 • (RSW)(DC)  
RSW = LT1172 switch “on” resistance (1maximum)  
Total power dissipation is the sum of supply current times  
input voltage plus switch power:  
Extra Pins on the MiniDIP and Surface Mount Packages  
PD(TOT) = (IIN)(VIN) + PSW  
The 8- and 16-pin versions of the LT1172 have the  
emitters of the power transistor brought out separately  
from the ground pin. This eliminates errors due to ground  
pin voltage drops and allows the user to reduce switch  
currentlimit2:1byleavingthesecondemitter(E2)discon-  
nected. The first emitter (E1) should always be connected  
tothegroundpin.Notethatswitchonresistancedoubles  
when E2 is left open, so efficiency will suffer somewhat  
In a typical example, using a boost converter to generate  
12V at 0.12A from a 5V input, duty cycle is approximately  
60%, and switch current is about 0.65A, yielding:  
IIN = 6mA + 0.65(0.004 + DC/40) = 18mA  
PSW = (0.65)2 • (1)(0.6) = 0.25W  
PD(TOT) = (5V)(0.018A) + 0.25 = 0.34W  
*See note under block diagram.  
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