欢迎访问ic37.com |
会员登录 免费注册
发布采购

E4991B-007 参数 Datasheet PDF下载

E4991B-007图片预览
型号: E4991B-007
PDF下载: 下载PDF文件 查看货源
内容描述: [Impedance Analyzer]
分类和应用:
文件页数/大小: 42 页 / 7850 K
品牌: KEYSIGHT [ Keysight Technologies ]
 浏览型号E4991B-007的Datasheet PDF文件第34页浏览型号E4991B-007的Datasheet PDF文件第35页浏览型号E4991B-007的Datasheet PDF文件第36页浏览型号E4991B-007的Datasheet PDF文件第37页浏览型号E4991B-007的Datasheet PDF文件第38页浏览型号E4991B-007的Datasheet PDF文件第40页浏览型号E4991B-007的Datasheet PDF文件第41页浏览型号E4991B-007的Datasheet PDF文件第42页  
39 | Keysight | E4991B Impedance Analyzer - Data Sheet  
Typical Effects of Temperature Change on Permeability  
Measurement Accuracy  
When the temperature at the test port (7-mm connector) of the high temperature cable  
changes more than 5 °C from the calibration temperature, the typical permeability mea-  
surement accuracy involving temperature dependence effects (errors) is applied. The  
typical permeability accuracy is represented by the sum of error due to temperature coef-  
ficient (Tc), hysteresis error (Tc × ΔTmax) and the accuracy at 23 °C ± 5 °C.  
Typical accuracy of permeability parameters:  
Δµ´  
r m  
µr´ accuracy  
=
:
µ´  
r m  
± (Eµ + Eh + Ei ) [%]  
.
Loss tangent accuracy of µr (= Δtand) :  
(Eµ + Eh + Ei )  
±
100  
where,  
Eµ  
=
Permeability measurement accuracy  
at 23 °C ± 5 °C  
Eh  
=
=
=
Tc × ΔT × 100  
Ei  
Tc × ΔTmax × 0.3 × 100  
K4 + K5 + K6  
Tc [°C-1]  
See Figure 57 through Figure 59 for the  
calculated value of T  
c
without temperature compensation  
K4 [°C-1]  
=
1 × 10-6 × (60 + 150 × ƒ)  
K5 [°C-1]  
=
|1 – 0.01 × {F × (µr´ m – 1) + 10} × ƒ2|  
1 × 10-2 × (1 + 10 × ƒ) ×  
{F × (µ´ 1) + 20} × ƒ  
r m  
K6 [°C-1]  
=
{F × (µ´ – 1) + 20} × ƒ  
|1 – 0.01 × {F × (µr´ m –1) + 10} × ƒ2|  
r m  
2 × 10-6 × (0.3 + 3 × ƒ) ×  
with temperature compensation  
K4  
K5  
=
=
1 × 10-6 × (60 + 150 × ƒ)  
at 1 MHz ≤ ƒ < 500 MHz  
|1 – 0.01 × {F × (µr´ m – 1) +10} × ƒ2|  
1 × 10-2 × (1 + 10 × ƒ) ×  
{F × (µ´ – 1) + 20} × ƒ  
r m  
at 500 MHz ≤ ƒ ≤ 1 GHz  
|1 – 0.01 × {F × (µr´ m – 1) +10} × ƒ2|  
1 × 10-2 × (5 + 2 × ƒ) ×  
{F × (µ´ 1) + 20} × ƒ  
r m  
 复制成功!