RATING CHARACTERISTIC CURVES ( 2SC2411KPT )
Fig.4 Collector-emitter saturation voltage
vs. collector current
Fig.5 DC current gain vs.
collector current
Fig. 6 Gain bandwidth product
vs. emitter current
1
1000
500
500
25OC
10
VCE=3V
Ta 25OC
=
VCE 5V
=
Ta
=
B
lC/l
=
0.5
200
100
50
200
100
50
0.2
0.1
OC
5
2
0.05
20
10
0.02
0.5
0.1 0.2 0.5
1
2
5 10 20 50 100 200 5001000
0.5
1
2
5
10
20
50
1
2
5
10 20
50 100 200 500 1000
COLLECTOR CURRENT : I (mA)
C
COLLECTOR CURRENT : I
C(
mA)
EMITTER CURRENT : IE mA)
(
Fig.7 Collector output capacitance vs.
collector-base voltage
Emitter input capacitance vs.
emitter-base voltage
Ta 25OC
=
50
f
I
I
1MHz
=
E
0A
0A
=
C
=
20
10
5
2
0.5
1
2
5
10
20
50
V)
COLLECTOR TO BASE VOLTAGE : VCB
EMITTER TO BASE VOLTAGE : VEB
(
(
V)
CHENMKO [ CHENMKO ENTERPRISE CO. LTD. ]
