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AAT2784IRN-AAA-T1 参数 Datasheet PDF下载

AAT2784IRN-AAA-T1图片预览
型号: AAT2784IRN-AAA-T1
PDF下载: 下载PDF文件 查看货源
内容描述: 3通道降压型DC / DC转换器 [3-Channel Step-Down DC/DC Converter]
分类和应用: 转换器
文件页数/大小: 21 页 / 688 K
品牌: ANALOGICTECH [ ADVANCED ANALOGIC TECHNOLOGIES ]
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PRODUCT DATASHEET  
AAT2784  
SystemPowerTM  
3-Channel Step-Down DC/DC Converter  
Always examine the ceramic capacitor DC voltage coef-  
ficient characteristics when selecting the proper value.  
For example, the capacitance of a 10μF, 6.3V, X5R  
ceramic capacitor with 5.0V DC applied is actually about  
6μF. The maximum input capacitor RMS current is:  
0.75 VO  
m
0.75 1.2V  
A
0.75  
µs  
L =  
=
= 1.2µH  
The inductor should be set equal to the output voltage  
numeric value in micro henries (μH). This guarantees  
that there is sufficient internal slope compensation.  
Manufacturer’s specifications list both the inductor DC  
current rating, which is a thermal limitation, and the  
peak current rating, which is determined by the satura-  
tion characteristics. The inductor should not show any  
appreciable saturation under normal load conditions.  
Some inductors may meet the peak and average current  
ratings yet result in excessive losses due to a high DCR.  
Always consider the losses associated with the DCR and  
its effect on the total converter efficiency when selecting  
an inductor. For channel 3, the 1.5μH LQH32PN1R5NN0L  
series Murata inductor has a 68.4mΩ worst case DCR  
and a 1.75A DC current rating. At full 1.5A load, the  
inductor DC loss is 154mW which gives less than 5%  
loss in efficiency for a 1.5A, 1.2V output.  
VO  
VIN  
VO  
VIN  
IRMS = IO ·  
· 1 -  
The input capacitor RMS ripple current varies with the  
input and output voltage and will always be less than or  
equal to half of the total DC load current.  
VO  
VIN  
VO  
VIN  
1
2
· 1 -  
=
D · (1 - D) = 0.52 =  
for VIN = 2 · VO  
IO  
IRMS(MAX)  
=
2
Input Capacitor  
The term appears in both the input voltage ripple and  
input capacitor RMS current equations and is a maxi-  
mum when VO is twice VIN. This is why the input voltage  
ripple and the input capacitor RMS current ripple are a  
maximum at 50% duty cycle. The input capacitor pro-  
vides a low impedance loop for the edges of pulsed cur-  
rent drawn by the AAT2784. Low ESR/ESL X7R and X5R  
ceramic capacitors are ideal for this function. To mini-  
mize stray inductance, the capacitor should be placed as  
closely as possible to the IC. This keeps the high fre-  
quency content of the input current localized, minimizing  
EMI and input voltage ripple. The proper placement of  
the input capacitor (C1) can be seen in the evaluation  
board layout in the Layout section of this datasheet (see  
Figure 2). A laboratory test set-up typically consists of  
two long wires running from the bench power supply to  
the evaluation board input voltage pins. The inductance  
of these wires, along with the low-ESR ceramic input  
capacitor, can create a high Q network that may affect  
converter performance. This problem often becomes  
apparent in the form of excessive ringing in the output  
voltage during load transients. Errors in the loop phase  
and gain measurements can also result. Since the induc-  
tance of a short PCB trace feeding the input voltage is  
significantly lower than the power leads from the bench  
power supply, most applications do not exhibit this prob-  
lem. In applications where the input power source lead  
inductance cannot be reduced to a level that does not  
Select a 10μF to 22μF X7R or X5R ceramic capacitor for  
the VP1_2 and VP3 inputs. To estimate the required  
input capacitor size, determine the acceptable input  
ripple level (VPP) and solve for CIN. The calculated value  
varies with input voltage and is a maximum when VIN is  
double the output voltage.  
Output  
Slope  
Conguration Voltage Inductor Compensation  
0.6V-  
2.2μH  
0.6V adjustable  
with external  
resistive divider  
2.0V  
2.5V  
3.3V  
0.6A/μs  
3.3μH  
4.7μH  
Table 1: AAT2784 Inductor Values.  
VO  
VIN  
VO  
VIN  
· 1 -  
CIN =  
VPP  
IO  
- ESR ·FS  
VO  
VIN  
VO  
VIN  
1
· 1 -  
=
for VIN = 2 · VO  
4
1
CIN(MIN)  
=
VPP  
IO  
- ESR · 4 · FS  
w w w . a n a l o g i c t e c h . c o m  
2784.2007.11.1.1  
13  
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