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AAT2514_08 参数 Datasheet PDF下载

AAT2514_08图片预览
型号: AAT2514_08
PDF下载: 下载PDF文件 查看货源
内容描述: 双通道600mA降压转换器 [Dual Channel 600mA Step-Down Converter]
分类和应用: 转换器
文件页数/大小: 14 页 / 576 K
品牌: ANALOGICTECH [ ADVANCED ANALOGIC TECHNOLOGIES ]
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PRODUCT DATASHEET  
AAT2514  
SwitchRegTM  
Dual Channel 600mA Step-Down Converter  
Therefore:  
To minimize stray inductance, the capacitor should be  
placed as closely as possible to the IC. This keeps the  
high frequency content of the input current localized,  
minimizing EMI and input voltage ripple. The proper  
placement of the input capacitor (C1) can be seen in the  
evaluation board layout in Figure 3. A laboratory test set-  
up typically consists of two long wires running from the  
bench power supply to the evaluation board input voltage  
pins. The inductance of these wires, along with the low-  
ESR ceramic input capacitor, can create a high Q net-work  
that may affect converter performance. This problem  
often becomes apparent in the form of excessive ringing  
in the output voltage during load transients. Errors in the  
loop phase and gain measurements can also result. Since  
the inductance of a short PCB trace feeding the input volt-  
age is significantly lower than the power leads from the  
bench power supply, most applications do not exhibit this  
problem. In applications where the input power source  
lead inductance cannot be reduced to a level that does  
not affect the converter performance, a high ESR tanta-  
lum or aluminum electrolytic should be placed in parallel  
with the low ESR, ESL bypass ceramic. This dampens the  
high Q network and stabilizes the system.  
2.5  
m
L =  
= 2.2µH  
With these adaptive settings, a 2.2μH inductor can be  
used for all output voltages from 0.6V to 5V.  
Input Capacitor Selection  
The input capacitor reduces the surge current drawn  
from the input and switching noise from the device. The  
input capacitor impedance at the switching frequency  
shall be less than the input source impedance to prevent  
high frequency switching current passing to the input.  
The calculated value varies with input voltage and is a  
maximum when VIN is double the output voltage.  
VO  
VO ⎞  
VIN  
· 1 -  
VIN  
CIN =  
VPP  
IO  
- ESR ·FS  
VO  
VO ⎞  
VIN ⎠  
1
· 1 -  
=
for VIN = 2 · VO  
VIN  
4
Output Capacitor Selection  
1
CIN(MIN)  
=
VPP  
The function of output capacitance is to store energy to  
attempt to maintain a constant voltage. The energy is  
stored in the capacitor’s electric field due to the voltage  
applied.  
- ESR · 4 · FS  
IO  
A low ESR input capacitor sized for maximum RMS cur-  
rent must be used. Ceramic capacitors with X5R or X7R  
dielectrics are highly recommended because of their low  
ESR and small temperature coefficients. A 22μF ceramic  
capacitor for most applications is sufficient. A large value  
may be used for improved input voltage filtering.  
The value of output capacitance is generally selected to  
limit output voltage ripple to the level required by the  
specification. Since the ripple current in the output induc-  
tor is usually determined by L, VOUT, and VIN, the series  
impedance of the capacitor primarily determines the out-  
put voltage ripple. The three elements of the capacitor  
that contribute to its impedance (and output voltage  
ripple) are equivalent series resistance (ESR), equivalent  
series inductance (ESL), and capacitance (C). The out-  
put voltage droop due to a load transient is dominated by  
the capacitance of the ceramic output capacitor. During a  
step increase in load current, the ceramic output capaci-  
tor alone supplies the load current until the loop  
responds. Within two or three switching cycles, the loop  
responds and the inductor current increases to match the  
load current demand. The relationship of the output volt-  
age droop during the three switching cycles to the output  
capacitance can be estimated by:  
The maximum input capacitor RMS current is:  
VO  
VO ⎞  
IRMS = IO ·  
· 1 -  
VIN  
VIN  
The input capacitor RMS ripple current varies with the  
input and output voltage and will always be less than or  
equal to half of the total DC load current  
VO  
VO ⎞  
VIN ⎠  
1
2
· 1 -  
=
D · (1 - D) = 0.52 =  
IO  
VIN  
IRMS(MAX)  
=
2
3 · ΔILOAD  
=
COUT  
V
DROOP · FS  
w w w . a n a l o g i c t e c h . c o m  
2514.2008.02.1.1  
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