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T9000 参数 Datasheet PDF下载

T9000图片预览
型号: T9000
PDF下载: 下载PDF文件 查看货源
内容描述: ISDN网络终端节点( NTN )设备 [ISDN Network Termination Node (NTN) Device]
分类和应用: 综合业务数字网
文件页数/大小: 126 页 / 1581 K
品牌: AGERE [ AGERE SYSTEMS ]
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T9000  
Preliminary Data Sheet  
November 2000  
ISDN Network Termination Node (NTN) Device  
To further understand the operation of the PWSM mod-  
ule, consider the math behind the operation. The sine  
wave being generated can be described by the follow-  
ing equation:  
12 PWM Module (continued)  
12.4 PWM Auto Mode Example  
Consider an example of how to set up the PWM mod-  
ule in auto mode. Suppose we want to generate a sine  
wave of frequency Fs. First select the values of range  
and granularity, and then compute the appropriate  
value of PWxVH/L. To accomplish this, the procedure  
is as follows:  
f(t) = Asin (2π x Fa x t)  
(10)  
where Fa is computed per equation 8. A new value for  
this equation is computed every pulse period, PP.  
Therefore, in the nth pulse period (where n is an inte-  
ger representing the current sample number, beginning  
with sample 0), the time (t) in the above equation is:  
Calculate the pulse period, PP, (from equation 2)  
PP = Range x Granularity x 65 ns  
(3)  
(4)  
t = n x PP  
(11)  
Calculate the sine period, SP:  
1
Substituting equation 11 into equation 10 yields:  
------  
FS  
SP =  
f(t) = Asin (2π x Fa x n x PP)  
(12)  
Based on PP and SP, we can calculate the number of  
samples (Ks) per sine period:  
Now rearranging equation 8,  
1
SP  
--------  
SP  
--------------------------------------------------------------------------------------  
Ks =  
=
(5)  
----------------------  
PP =  
(13)  
PP Range × Granularity × 65 ns  
Fa × Ka  
Now calculate the 16-bit quantity PWV (i.e., PWVxH/L,  
the amount by which the accumulator will increment  
each time as shown in Figure 22). There are 216 total  
addresses in one sine period, SP. Since there are Ks  
samples in one sine period, 216 must be divided by Ks  
so that exactly one cycle of all 216 addresses has been  
completed in one sine period, SP. The rounded result is  
PWV, which gets written into the PWxVH and PWxVL  
registers:  
and substituting the value of Ka computed in equation  
7 results in:  
PWV  
Fa × 216  
-----------------------  
PP =  
(14)  
Substituting equation 14 into equation 12 yields:  
n × PWV  
-----------------------  
f(t) = Asin (2π  
)
(15)  
216  
216  
---------  
KS  
PWV = ROUND  
=
From equation 15, it is evident that the argument gen-  
erated sine wave is n x PWV. This term is generated at  
the output of the accumulator shown in Figure 22 by  
clocking the accumulator at PP intervals. The maxi-  
mum value of n x PWV is 216 because the accumulator  
will roll over after it reaches 216. Therefore, the factor of  
216 in the denominator is the normalization factor,  
which is equal to the maximum value of n x PWM.  
216 × Range × Granularity × 65 ns  
------------------------------------------------------------------------------------------------------  
ROUND  
(6)  
SP  
Now, back-calculate the actual number of samples (Ka)  
based on the rounded result:  
216  
PWV  
---------------  
Ka =  
(7)  
To find the error in frequency due to rounding, first  
back-calculate the actual frequency of the sine modula-  
tor output by taking the inverse of the pulse period  
times the actual number of samples, as follows:  
1
-----------------------  
Fa =  
(8)  
PP × Ka  
Then calculate the error in frequency as:  
Fa FS  
---------------------  
FS  
Ferr =  
x 100%  
(9)  
Lucent Technologies Inc.  
97  
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