AD8132
25
20
15
10
G = 2 ,R
F
= 1kΩ
5
0
–5
–10
–15
G = 1 ,R
F
= 499Ω
G = 10 ,R
F
= 4.99kΩ
G = 5 ,R
F
= 2.49kΩ
–30
–40
–50
失真( DBC)
–60
–70
–80
–90
–100
01035-020
R
L, DM
= 800Ω
V
O, DM
= 2V峰 - 峰值
HD3 (V
S
= +5V)
HD2 (V
S
= ±5V)
HD3 (V
S
= ±5V)
HD2 (V
S
= +5V)
增益(dB )
V
S
= ±5V
V
O, DM
= 2V峰 - 峰值
R
L, DM
= 200Ω
R
G
= 499Ω
1
10
100
频率(MHz)
1k
0
10
20
30
40
频率(MHz)
50
60
70
图17.大信号频率响应为各种增益
(参见图58)
–25
–30
–35
V
S
= ±5V
ΔV
O, DM
= 2V峰 - 峰值
ΔV
O,厘米
/ΔV
O, DM
图20.谐波失真与频率的关系,G = 1 (见图62 )
–40
–50
–60
失真( DBC)
V
S
= 3V
R
L, DM
= 800Ω
HD3 ( F = 20MHz的)
RTI平衡ERROR (分贝)
–40
–45
–50
–55
–60
G=2
–65
–70
01035-022
HD2 ( F = 20MHz的)
G=1
–70
–80
–90
–100
HD2 (F = 5MHz时)
HD3 (F = 5MHz时)
01035-026
–75
1
10
100
频率(MHz)
1k
–110
0.25
0.50
0.75
1.00
1.25
1.50
差分输出电压(V P-P )
1.75
图18. RTI输出平衡误差与频率的关系(参见图59)
–40
–50
–60
失真( DBC)
–70
–80
HD2 (V
S
= 5V)
–90
–100
HD3 (V
S
= 5V)
01035-024
图21.谐波失真与
差分输出电压,G = 1(参见图62)
–40
V
S
= 5V
R
L, DM
= 800Ω
R
L, DM
= 800Ω
V
O, DM
= 1V P-P
HD3 (V
S
= 3V)
–50
–60
HD3 ( F = 20MHz的)
失真( DBC)
HD2 (V
S
= 3V)
–70
–80
–90
–100
–110
0
1
2
3
差分输出电压(V P-P )
4
HD2 (F = 5MHz时)
HD2 ( F = 20MHz的)
HD3 (F = 5MHz时)
01035-027
–110
0
10
20
30
40
频率(MHz)
50
60
70
图19.谐波失真与频率的关系,G = 1 (见图62 )
图22.谐波失真与
差分输出电压,G = 1(参见图62)
修订版F |第12页32
01035-025
–110