OP1177/OP2177/OP4177
In the single instrumentation amplifier (see Figure 63), where
PROPER BOARD LAYOUT
R4
R3
R2
R1
The OPx177 is a high precision device. To ensure optimum
performance at the PCB level, care must be taken in the design
of the board layout.
=
R2
VO =
(
V2 −V1
)
R1
To avoid leakage currents, the surface of the board should be
kept clean and free of moisture. Coating the surface creates a
barrier to moisture accumulation and helps reduce parasitic
resistance on the board.
a mismatch between the ratio R2/R1 and R4/R3 causes the
common-mode rejection ratio to be reduced.
To better understand this effect, consider that, by definition,
Keeping supply traces short and properly bypassing the power
supplies minimizes power supply disturbances due to output
current variation, such as when driving an ac signal into a heavy
load. Bypass capacitors should be connected as closely as possible
to the device supply pins. Stray capacitances are a concern at the
outputs and the inputs of the amplifier. It is recommended that
signal traces be kept at least 5 mm from supply lines to
minimize coupling.
ADM
CMRR =
ACM
where ADM is the differential gain and ACM is the common-
mode gain.
VO
VDIFF
VO
VCM
ADM
=
and ACM =
1
2
A variation in temperature across the PCB can cause a mismatch in
the Seebeck voltages at solder joints and other points where dissi-
milar metals are in contact, resulting in thermal voltage errors. To
minimize these thermocouple effects, orient resistors so heat
sources warm both ends equally. Input signal paths should contain
matching numbers and types of components, where possible to
match the number and type of thermocouple junctions. For
example, dummy components such as zero value resistors can
be used to match real resistors in the opposite input path.
Matching components should be located in close proximity and
should be oriented in the same manner. Ensure leads are of equal
length so that thermal conduction is in equilibrium. Keep heat
sources on the PCB as far away from amplifier input circuitry as
is practical.
VDIFF = V1 −V2 andVCM
=
(
V1 +V2
)
For this circuit to act as a difference amplifier, its output must
be proportional to the differential input signal.
From Figure 63,
R2
R1
R3
⎡
⎢
⎢
⎢
⎤
⎥
⎥
⎥
⎛
⎜
⎝
⎛
⎜
⎝
⎞
⎟
⎠
⎞
⎟
⎠
1+
1+
R2
R1
⎛
⎜
⎝
⎞
⎟
⎠
V = −
V +
V2
1
O
⎢
⎣
⎥
⎦
R4
Arranging terms and combining the previous equations yields
R4R1+ R3R2 + 2R4R2
CMRR =
(1)
2R4R1−2R2R3
The use of a ground plane is highly recommended. A ground
plane reduces EMI noise and also helps to maintain a constant
temperature across the circuit board.
The sensitivity of CMRR with respect to the R1 is obtained by
taking the derivative of CMRR, in Equation 1, with respect to R1.
δCMRR
δR1
δ
R1R4
2R2R4 + R2R3
DIFFERENCE AMPLIFIERS
⎛
⎝
⎞
⎟
⎠
=
=
+
⎜
δR1 2R1R4 −2R2R3 2R1R4 −2R2R3
Difference amplifiers are used in high accuracy circuits to improve
the common-mode rejection ratio (CMRR).
δCMRR
δR1
1
(
2R2R3)
R2
100kΩ
2 −
R1R4
V+
Assuming that
7
R1
2
3
V1
V2
6
V
R1 ≈ R2 ≈ R3 ≈ R4 ≈ R
OUT
OP1177
4
and
V–
R(1 − δ) < R1, R2, R3, R4 < R(1 + δ)
R3 = R1
R4 = R1
R4 R2
R3 R1
the worst-case CMRR error arises when
=
Figure 63. Difference Amplifier
R1 = R4 = R(1 + δ) and R2 = R3 = R(1 − δ)
Rev. G | Page 18 of 24
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