AD8072/AD8073
100
V
S
=
100
A
V
=
OUTPUT RESISTANCE –
5V
INPUT CURRENT NOISE – pA/ Hz
R
F
= 1k
2
80
10
60
40
1
20
0.1
0.1
0
1
10
FREQUENCY – MHz
100
500
1
10
100
1k
FREQUENCY – Hz
10k
100k
Figure 16. Output Resistance vs. Frequency; V
S
=
±
5 V
Figure 18. Noise vs. Frequency; V
S
=
±
5 V
50
10
0
V
S
= 5V
R
F
= 1k
R
L
= 150
A
V
= 2
100mV p-p ON TOP
OF V
S
INPUT VOLTAGE NOISE – nV/ Hz
40
–10
–20
–30
–40
–PSRR
20
PSRR – dB
30
PSRR
–50
10
–60
0
1
10
100
1k
FREQUENCY – Hz
10k
100k
–70
0.02
0.1
1
10
FREQUENCY – MHz
100
500
Figure 17. Noise vs. Frequency; V
S
=
±
5 V
Figure 19. PSRR vs. Frequency
–5
–10
–15
–20
CMRR – dB
V
IN
2V p-p
1k
1k
154
60.4
154
V
OUT
150
–25
–30
–35
–40
–45
–50
–55
0.02
0.1
1
10
FREQUENCY – MHz
100
500
Figure 20. CMRR vs. Frequency; V
S
=
±
5 V
REV. A
–7–
AD [ ANALOG DEVICES ]
