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AL10053N2DL 参数 Datasheet PDF下载

AL10053N2DL图片预览
型号: AL10053N2DL
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内容描述: 薄膜片式电感器 [THIN FILM CHIP INDUCTOR]
分类和应用: 电感器
文件页数/大小: 66 页 / 368 K
品牌: ABC [ ABC Taiwan Electronics Corp ]
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AL103 Revision 1.0  
3.7.3 Trunk Port Assignment  
The maximum number of trunks for the AL103 is two. The Port Configuration I registers provide  
the ability to designate a port to be a member of a trunk. The trunk can consist of up to four trunk  
ports. A trunk group must consist of either the top four ports or the bottom four ports, for example a  
trunk can consist of port 0 through port 3 or port 4 through port 7. Each trunk port’s number is in  
sequence of 00, 01, 10, and 11 corresponding to the order of port of the devices. For example, port  
1 and 5 are 01 (See Figure 4).  
AL103  
Ports  
1
2
3
4
5
6
7
0
Trunk Port 1  
Trunk Port 0  
Figure 4  
Trunk Port Numbering  
3.7.4 Port Based Trunk Load Balancing  
For port-based load balancing, a trunk port must be assigned to each port for all defined trunks. The  
port assignment is done by programming Port to Trunk Port Registers (2E to 35). A port assignment  
worksheet is provided at the back of the data sheet. It is recommended that ports be evenly  
distributed among all trunk ports to prevent overloading any single trunk port.  
Port Based Load Balancing Set up Example  
Note: Register bits are reference by X.Y, where “X” is the register number and “Y” is the bit  
number. Appendix I and II provide a worksheet for port to trunk port and VLAN assignment.  
The example is designing an 8-port switch with a 3-port based loading trunk. The desired trunk  
ports are 5, 6, and 7. We want to assign port 0 to trunk port 5, port 1 and 3 to trunk port 6, and port  
2 and 4 to trunk port 7.  
1. The Port Configuration I register bits 15.9, 16.9, and 17.9 are set to 1. This assigns  
ports 5, 6, and 7 as a trunk port.  
2. Assign port 0 to trunk port 5, port 1 and 3 to trunk port 6, and port 2 and 4 to trunk  
port 7. Therefore, set port to trunk port register bits.  
2E.2= 0, 2E.3 =1  
2F.2= 1, 2F.3 =0  
30.2= 1, 30.3 =1  
31.2= 1, 31.3 =0  
32.2= 1, 32.3 =1  
9/00  
Reference Only / Allayer Communications  
22  
 
 
 
 
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