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AAT3236IJS-2.5-T1 参数 Datasheet PDF下载

AAT3236IJS-2.5-T1图片预览
型号: AAT3236IJS-2.5-T1
PDF下载: 下载PDF文件 查看货源
内容描述: 300毫安CMOS高性能LDO [300mA CMOS High Performance LDO]
分类和应用:
文件页数/大小: 18 页 / 227 K
品牌: AAT [ ADVANCED ANALOG TECHNOLOGY, INC. ]
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AAT3236  
300mA CMOS High Performance LDO  
For a 500mA output current and a 1.2 volt drop  
across the AAT3236 at an ambient temperature of  
25°C, the maximum on-time duty cycle for the  
device would be 87.57%.  
VOUT  
IOUT  
IGND  
= 3.0V  
= 500mA  
= 150μA  
The following family of curves show the safe oper-  
ating area for duty-cycled operation from ambient  
room temperature to the maximum operating level.  
526mW + (3.0V × 500mA)  
VIN(MAX)  
=
500mA + 150μA  
VIN(MAX) = 4.05V  
Device Duty Cycle vs. VDROP  
(VOUT = 2.5V @ 25°C)  
From the discussion above, PD(MAX) was deter-  
mined to equal 526mW at TA = 25°C.  
3.5  
200 mA  
3
500 mA  
2.5  
Thus, the AAT3236 can sustain a constant 3V output  
at a 500mA load current as long as VIN is 4.05V at  
an ambient temperature of 25°C.  
2
400 mA  
1.5  
1
300 mA  
0.5  
0
Higher input-to-output voltage differentials can be  
obtained with the AAT3236, while maintaining device  
functions within the thermal safe operating area. To  
accomplish this, the device thermal resistance must  
be reduced by increasing the heat sink area or by  
operating the LDO regulator in a duty-cycled mode.  
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
Duty Cycle (%)  
Device Duty Cycle vs. VDROP  
(VOUT = 2.5V @ 50°C)  
For example, an application requires VIN = 4.2V  
while VOUT = 3.0V at a 500mA load and TA = 25°C.  
VIN is greater than 4.05V, which is the maximum  
safe continuous input level for VOUT = 3.0V at  
500mA for TA = 25°C. To maintain this high input  
voltage and output current level, the LDO regulator  
must be operated in a duty-cycled mode. Refer to  
the following calculation for duty-cycle operation:  
3.5  
200 mA  
3
2.5  
2
100 mA  
500 mA  
400 mA  
1.5  
1
300 mA  
0.5  
0
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
IGND = 150μA  
IOUT = 500mA  
VIN = 4.2V  
VOUT = 3.0V  
Duty Cycle (%)  
Device Duty Cycle vs. VDROP  
(VOUT = 2.5V @ 85°C)  
3.5  
3
100 mA  
PD(MAX)  
2.5  
2
%DC = 100  
(VIN - VOUT)IOUT + (VIN × IGND  
)
200 mA  
1.5  
1
526mW  
(4.2V - 3.0V)500mA + (4.2V × 150μA)  
%DC = 100  
500 mA  
400 mA  
0.5  
0
300 mA  
%DC = 87.57%  
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
PD(MAX) is assumed to be 526mW.  
Duty Cycle (%)  
12  
3236.2007.03.1.4